How do you do subnetting for these?

By learning how to subnet

>>62331967
how do I subnet?

Literally Google it

>>62331767
what is the question, even?

>>62332151
it's in the post

>>62332287
that post makes no sense. what is it you want to do with those subnets?

>>62332326
get the delta borrowed bits, number of subnets, host bits, usable host bits, subnet mask, and the table

>>62332368
Math

>>62332383
got any equations?

File: 440px-Quadratic_formula.svg.png (4KB, 440x136px) Image search: [Google]

4KB, 440x136px

>>62332537

>>62331767
A subnet mask in IPv4 consists of a total of 32 bits, which can be represented in binary mode as such: 00000000 00000000 00000000 00000000

A subnet mask's purpose, mind you, is also to mark the part of the IP address that identifies the network itself, and seperate it from the part used to numerate the different members of the network. The netmask is therefore a sequence of 1 bits with no 0 gaps, to further this separation.
In a subnet mask, a 255 would mean that the corresponding byte in the IP address is part of the network ID.
The first byte after the network ID in a class-derived IP address (class A, (255.0.0.0) class B, (255.255.0.0) etc.) would usually be referred to as the subnet ID, whereas the consecutive byte would be a host ID.
However, IP addresses don't always work that way, and sometimes you might encounter a subnet mask address where a particular byte shares parts of both the network ID and subnet/mask ID.

So for example, 192.168.1.0/24 would have a subnet mask of (11111111 11111111 11111111 00000000), which translated to decimal base is 255.255.255.0.

However, 10.0.0.0/19 would have a subnet mask of (11111111 11111111 11100000 00000000), that is -- 255.255.224.0
looking at the 11100000 bit of the subnet mask, 111 is part of the networkID, while 00000 is part of the host ID, leaving us with a number of 2^13 = 8192 potential hosts in this particular network.

You calculate the bottom-border address of the network IP range by ANDing the given IP address with the subnet mask (Think of it that way: the network part of the netmask is made up of 1 bits, so ANDing the netmask with the given IP address, we would get the original network ID. however, ANDing the host bit would leave us with nothing but zeroes, leaving us with the lowest possible address in this network).

The upper-border address could be found by ORing with the hostnet (which is the subnet NANDed by itself), giving us the forumla: UPPER_ADDR = GIVEN_ADDR OR (SUBNET NAND SUBNET).

>>62332732
Going back to 10.0.0.0/19, the bottom-border IP address would be 10.0.0.0 AND 255.255.224.0 = 10.0.0.0, and the upper one would be:

HOSTNET = SUBNET NAND SUBNET = 11111 11111111

UPPER_ADDR = GIVEN_ADDR OR HOSTNET = (OR
00001010 00000000 00000000 00000000
00000000 00000000 00011111 11111111)
= 00001010 00000000 00011111 11111111
= 10.0.32.255 -- which is also the broadcast address of this network (the last possible host for this network would therefore be 10.0.32.254).

>>62332102
You are paying your college class for that information.

Otherwise, drop out.

>>62332963
not really
you pay college for a degree

>>62332999
Which you're never going to get because you can't figure out how something as simple as subnets work.

>>62331767
it's a bitmask
the number after the slash is the number of bits that you want to stay unchanged
the rest can take on any value
the set of all possible 32bit values that satisfy these conditions is the subnet

>>62331767
With as little offense as humanly possible, if you're unwilling/incapable of learning how to do subnets then you are never going to hold even something as simple as an N+ or CCNA. Consider another career choice.