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So here's the situation. That's me standing on the beam and I weigh 100kg. A crane hook is attached to the end of the beam imparting an upward force on the beam of 936.92865 Newtons (N) (a Newton is a unit of force attained by multiplying a mass such as 1 kilogram by an acceleration such as the gravitational constant 9.81 meters per second per second here on Earth, i.e. 1kg X 9.81 m/s^2 = 9.81N). What is the reaction force at the wall?
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>>56401967
Draw Fbd, sum forces for each axis, solve
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>I am so stupid that I don't understand the concept of torque
>>>/homework/
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how the fuck is the beam even straight
this question makes no sense
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>>56402011
I think the assumption is that the beam doesn't deform. It also doesn't have its own weight as well.
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All forces all vertical, upward forces are positive.
F_{wall} = - \sum F_{crane} - F_{person}
F_{wall} = - (936.93N - 100kg*9.81N/kg)
F_{wall} = 981N - 936.93N
F_{wall} = 44.07N
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>>56401967
>I weigh 100kg
you are fat
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>>56401967
Its the sum of both forces although keep in mind one has a different direction. The distance doesnt matter unless youre concerned with momentum.
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