You should be able to solve this

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Shit wrong image

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>>159406553
The first one was better

>>159406553
14

Why have there been so many more Chio-chan threads lately?

>>>/sci/9015777

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>>159406910
Anime PV recently came out. I think it made a lot of people picked it up.

>>159406553
Too lazy to calculate but let's see if I can throw something together

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>>159406553
I FUCKING LOVE M/a/TH

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>>159406553
>>159408603
Step 8: nah

>>159406553
Final solution is the result from an angle angle side triangle from the triangle formed by length A and the tip of the bottom triangle. The side of this triangle that needs to be figured out is formed by the apex of length A and the tip of the bottom triangle.

Figuring that length is done by determining the length of the unknown side of the large triangle and using the SSS relation to figure out the angle opposite to that side. Use that angle to subtract from 180° to obtain the angle necessary to figure out the SAS relationship of the 3 length, the angle we just obtained, and the 7 length. This guves us the length necessary for the ASA calculation we need to figure out length A. I don't want to calculate this out, so do the number crunching yourselves nerds, law of sines and law of cosines are your friends.

A=6.63

>>159409012
This is correct.

>>159406531
I would do so many things to Chio-chan.

>>159407031
What?
I don't know how to feel about this. On one hand I'm excited, but on the other I'm getting a bad feeling.

>>159406531
183/28

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>>159415210
Here's how to solve the easy way:
To find the length of the line what you want to do is extend the line from P to B' (the red line) to create the triangle A'PR'
Notice that this triangle is similar to the right triangle ABR with the 4/3 length ratio
Thus, if we know the length of A'P, we can find the length of PR'
To find the length of A'P, we need to find the length of A'B', which can be found by using the similar triangles ABC and A'B'C and noting the length of B'C' is 7(=BC)-4(=BB')=3 to get 12/7.
With A'B'=12/7 and B'P=7 known to get A'P=61/7, we use the similar triangles ABR and APR' to get the length of line A(=PR') to be 183/28