What is the volume of revolution of the area between the curves y=2x & y=x^2 when revolved about the x-axis, x=2, & y=4?
Respectively, of course.
int(0, 2) [Pi(2x)^2 - Pi(x^2)^2]dx
>>333191
What about around y=4?
>>333199
>int(0, 2) [Pi(4-x^2)^2 - Pi(4-2x)^2]dx
What about finding the volume of a square cross section using that area that is perpendicular to the x-axis?
Someone please, if I sound desperate it's because I am.