Hey guys, I'm suppose to find the equilibrium points of these and I hope I got them right? There are no solutions anywhere so just wanted to double check I'm not just doing it completely wrong. Also, a later question says one corresponds to mutual coexistence. I had thought that meant that for one of them both parts had to be non-zero so does this mean I got it wrong? Or is it simply the one with the alpha? Thanks in advance.
>>305235
Sorry thought I rotated the image
>>305235
You can see that (0, -1) and (-1, 0) can't be equilibrium solutions of the system if you substitute them into your system, but the other two solutions are correct.
Instead, take it by cases that P = 0, and then P nonzero, and similarly for each of those, take the cases that Q = 0 and Q nonzero, to avoid a contradiction in your solution.
One of your missing solutions should be immediately obvious, the other will involve expressions for both P and Q in terms of alpha.
>>305305
>a contradiction in your solution
Meaning, this is why you have two points that aren't equilibrium solutions. You introduced a contradiction by your assumptions in solving both columns separately.
Cheers mate
So, how's this? Guessing it's the last 4 I got?
hopeful bump
>>305571
You made an arithmetic mistake in solving for Q on the right side.
>Q(a-1) = 2
>...
There are 4 solutions. Two of your points are wrong.
You can check which ones are solutions by evaluating P' and Q' and checking that both are zero.
>>305791
ahhhh man I'm such a fool, thank you
Does anyone have an answer? I think I'm going round in circles finding the same stuff over and over again. I'm kinda slow