halp with homework? simple stuff solve each equation: 1/4x^2

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>>269532

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>>269534

https://www.wolframalpha.com/input/?i=1%2F4x%5E2+%2B+5%2F4%3D+-21%2F8x+solve+for+x

>>269548
thats a great website but wont let me see step by step without paying unfortunately

>>269557
https://www.symbolab.com/

>>269561
https://www.symbolab.com/solver/step-by-step/1%2F4x%5E%7B2%7D%20%2B%205%2F4%3D%20-21%2F8x

I got everything up to "Refine"

then after that it goes off the rails, we didn't cover that in my class

>>269561
got it, thank u sexy

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Alright OP, next time listen to your teacher.

I'm going to assume that the X isn't under the four, and is instead is outside the fraction.

First what you do is combine x with the numerator 1(On the left) so the operation now is :
X^2/4 + 5/4 = -21/8x
Now like both X^2/4 and 5/4 have the same denominator, you can merge them together to make one:
X^2+5/4 = -21/8x
Now combine the X to the -21 numerator like you did before on the first step. The operation would now be:
X^2+5/4 = -21x/8
Now Multiply both sides by 8 as its the LCM in this case. You will end up with :
2(x^2+5)= -21x
Now multiply the exponent to get:
2x^2+10=-21x
Now move -21x to the other side
2x^2+21x+10=0
I'm assuming that you can get it from here, but if not I understand.
I found it a bit tricky at first but what you have to do is split and use common factors as so:
You can split the term 21x into 20x+x :
2x^2+20x+x+10=0
With this, you can use common factoring on both sides to get
2x(x+10) + 1(x+10)
Which results in two solutions:
(X+10)= 0 AND (2x-1) = 0
So the 2 solutions are X= -10 and X= -1/2

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Your second problem is a lot quicker actually lmao:

243x^3=81x^4

243 and 81 are common factors to 81 and so you can divide them as such:

243/3 = 3 and 81/81 = 1 so

3x^3= x^4

Move all terms to one side, in this case I'm moving x^4 to the left
3x^3 - x^4 = 0

The common factor is x^3 so you factor those 2 :x^3(3-x) = 0

Now x(3-x)=0 when X=0 or X=3
So your solutions are X=0 and X=3.

By the way, we know you're a Junior taking Algebra II. We don't accept young fags and especially stupid fags, so stay out of 4chan

>>269576
a^3 - 5/3a^2b + 25/36ab^2

last one chief