Help me anon! How do I calculate the time it will take for the

1) t=sqrt((2*height)/g) = sqrt(10/10) = 1s ?

2) v=sqrt(2*g*height) = sqrt(100) = 10m/s?

Does not feel right to me. Can anyone, please, clarify about this horizontal projectile motion?

theres no force along the horizontal axis, just calculate for the vertical one. Use the y component

t={\frac {2v_{0}\sin(\theta )}{g}}

>>224924
the force was given by a guy who kicked the ball.

File: Screen Shot 2016-11-23 at 6.47.06 pm.png (9KB, 170x61px) Image search: [Google]

9KB, 170x61px

>>224924
fuck, this is it

use y = usin(/theta)

thnx all