Sup /wsr/ I have a math problem. Is it possible to determine

If you want the length of the line to have the size of 2 starting from [2,2], all you need to do is add sqrt(2) to x and y, in such a way that now the line will be from [2,2] to [2+sqrt(2), 2 + sqrt(2)]. This, of course, is because:
2^2 = sqrt(2)^2 + sqrt(2)^2
This is Pitagoras.

Is this really what you want?
Try drawing something on paint.

File: adding_segments.png (6KB, 640x400px) Image search: [Google]

6KB, 640x400px

>>210872
Thanks for replaying
I'm looking for pic related

>>210879
Then the first reply is exactly what you need.
Notice that sqrt(x) stands for square root of x and x^y stands for x to the power of y.
That being so, you can get here like this:
2^2 = x^2 + y^2 (Pythagoras)
4 = 2*x^2 (Since x = y)
2 = x^2 (divide both sides by 2)
x = sqrt(2) (Using only positive values for the sake of simplicity)
y = x = sqrt(2).

The line segment [sqrt(2), sqrt(2)] starting from [0,0] will have length 2. That being so, it's obvious that [2 + sqrt(2), 2 + sqrt(2)] starting from [2,2] will also have the same length.

Hope that helped.

Look at the circle with radius 2 around the point (2,2) and intersect it with the line.
You have to solve the system:

y = x
(x - 2)^2 + (y - 2)^2 = 4

Thanks anons, I appreciate Your help.