Because I know nothing of probability mathematics, I am wondering

>>55349870

1/2x1/2x1/2x1/2x1/2= 6.25% chance of getting 5 turns.

d10/2 round down gives you a 10% chance.
flip your damn coins.

No. The way you are describing it, every number has the same chance. In reality, 2-3 turns are moet likely, 1-4 somewhat less and 0/5 the least.

>>55349870
1d10/2 round down = { (0), (1), (1), (2), (2), (3), (3), (4), (4), (5)} with me listing repeated outcomes (e.g. chance of a 1 is 2/10, chance of 5 is 1./10).

5 coin flips is a binomial distribution.

Chance of 0 = 5C0 / 2^5 = 1/32
Chance of 1 = 5C1 / 2^5 = 5/32
Chance of 2 = 5C2 / 2^5 = 10/32
Chance of 3 = 5C3 / 2^5 = 10/32
Chance of 4 = 5C4 / 2^5 = 5/32
Chance of 5 = 5C5 / 2^5 = 1/32

Answer: Not even kind of.

File: 1490127103360.jpg (27KB, 296x341px) Image search: [Google]

27KB, 296x341px

>>55349870
>Because I know nothing of probability mathematics,

Don't they teach this stuff in elementary school?

>>55349923

Either not when I was attending or I never absorbed it at the time.

>>55349881
>>55349907

Thanks, I keep forgetting that a d(n) roll is a 1/(n) chance.

>>55349870
Just roll 5d6 and take an extra turn for each die that comes up 4+.

>>55350150
Or just 5d2, which is literally what flipping 5 coins is.

>>55349870
Run Krark's Thumb loser

>>55349923
Who remembers what they're taught in elementary?