What sorcery is this? How did these cucks get -t/T + C on the right side
>>>/sqt/ You retarded faggot.
[math]
\int 1 dt= t + C
[/math]
>>9065104
Just integrate both sides as they stand.
[eqn]\frac{dH(t)}{H(t)} = \frac{-dt}{\tau}[/eqn]
[eqn]\int{\frac{dH(t)}{H(t)}} = \int{\frac{-dt}{\tau}}[/eqn]
[eqn]\ln(H(t)) = -t/\tau + const[/eqn]
The const is a constant of integration.
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