So lets say there is this procedure where you have 50% of surviving

25%
you survive half of the first time and half of that time you survive
1/2*1/2 = 1/4

>>9023718
25% chance of surviving. This is basic probability (assuming you your chances are not reduced in the second for medical reasons).
The chance of an outcome in the first event will not affect the chance in the second. As such, you still have a 50% chance of surviving the second procedure regardless of the outcome of the first.
Before any procedure you have a 100% chance of survival
After the first procedure, you have a 50% chance of survival.
After the second procedure, you have a 50% chance of surviving again. 50% of 50% is 25%.

>>9023734
>>9023736
Hold on, wouldn't the doctor become more proficient at the procedure? So the risk should go down each time.

>>9023718
its 50%, either you die or you dont

>>9023747
Suppose x and y are positive numbers less than 1. Then x*y is a positive number less than both x, y, and 1.
With successive procedures, the risk can only increase.
For your example, if the doctor does improve to %75 the second time:
Out of 200 people, only 100 survive the first procedure. Out of the 100, 75 survive the second procedure. There are 100+25 dead; the dead will not come back.

33%

Three possible outcomes, die first procedure, live first procedure then die second procedure, or live first and second procedure. 1 positive outcome out of 3 is 1/3, or 33%

>>9023763
This.

>>9023718
It's random you can't know, or else it wouldn't be random by definition.

>>9023718
100% obviously, retard.

>>9024408
Came here to essentially post this

Anyone saying 25% is including the possibility of dying twice, which is silly

>>9024408
>>9025003
Yep, you both need to be executed.

>>9023747
Anon assumed indipendence.
Also this
>>9023764

>>9024408

But the 3 outcomes are not equal chances. "Die 1st procedure" is a 50% outcome, and the other 2 outcomes split the remaining 50%.

You have a 50% + 25% chance of dying in either of the 2 procedures.

Using the 33% theory, you can lower the casualty rate of a procedure merely by thinking about repeating it in the future.

50%

The question asks what the odds of surviving FOR both procedures, not surviving both procedures.

>>9025059
meaning you only have to survive the first procedure to have the second procedure, Doesn't matter if you live or die since you lived to have the second procedure. So yeah, 50%

>If you keep flipping a coin, it will eventually only land on one side every time!

It's straight up 50%

>>9025109
Nevermind I'm a bainlet