What does it converge to? [math] \displaystyle{\sum_{n=1}^{\infty}

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Anonymous
2017-06-08 10:46:46 Post No. 8963687
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Anonymous 2017-06-08 10:46:46 Post No. 8963687 [Report]

What does it converge to?

[math] \displaystyle{\sum_{n=1}^{\infty} \frac{1}{n^3 \cdot sin^2(n)}} [/math]

Anonymous 2017-06-08 10:49:55 Post No.8963689
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Anonymous 2017-06-08 10:49:55 Post No.8963689 [Report]

http://www.wolframalpha.com/input/?i=sum+n%5E-3+sin%5E-2+(n)+from+n%3D1+to+infinity

4.80672...

Anonymous 2017-06-08 10:52:32 Post No.8963693
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Anonymous 2017-06-08 10:52:32 Post No.8963693 [Report]

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>>8963689

but...

Anonymous 2017-06-08 10:58:42 Post No.8963696
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Anonymous 2017-06-08 10:58:42 Post No.8963696 [Report]

>>8963693
i'll trust wolfram over brainlets on stackexchange

Anonymous 2017-06-08 12:02:41 Post No.8963763
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Anonymous 2017-06-08 12:02:41 Post No.8963763 [Report]

>>8963689
>>8963696
click "more digits" and see what happens lol

Anonymous 2017-06-08 12:15:21 Post No.8963770
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Anonymous 2017-06-08 12:15:21 Post No.8963770 [Report]

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>>8963763

Anonymous 2017-06-08 12:19:35 Post No.8963774
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Anonymous 2017-06-08 12:19:35 Post No.8963774 [Report]

>>8963770
yeah i guess wolfram just outputs what you get after the first few hundred partial sums and can't account for sudden changes after

Anonymous 2017-06-08 02:06:09 Post No.8963879
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Anonymous 2017-06-08 02:06:09 Post No.8963879 [Report]

>>8963687
Easily converges. 1/sin(n) takes only values of O(n) at most. Experimentally verified.