I'm having an issue with our old friend Newton. If F=ma and we set a equal to g shouldn't a falling object hit the ground with the same amount of force regardless of the starting height because while the speed changed, acceleration remained constant.
>>8960284
No, [math] F=ma [/math] would give the force acting on the particle as it falls. You'd then have to use it again to find the force that the particle hits the ground with, ie. [math] a [/math] here would be come the deceleration from some speed [math] v [/math] to 0.
>>8960286
I get you. That makes sense