Hey /sci/fags, help me: I need to the area closest to the vertex in these two function (image related) from 0 to pi/2.
r=50sin(theta)
r=-15sin(3theta)+35
the two lines intercept at each other at .4256 and pi\2 in the integral.
I have done the first section so really i just need
int{.4256}^{\pi/2} ((1/2)(-15sin(3\theta)+35)^2 d\theta
solved
But my calculator keeps shitting out numbers that are way too big, what am I doing wrong?
>equation in LaTex
>all my math is under the assumption that the area under polar curves is represented as pic
OP: Nvm, figured it out