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Hey /sci/fags, help me: I need to the area closest to the vertex

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Thread replies: 4
Thread images: 3

Hey /sci/fags, help me: I need to the area closest to the vertex in these two function (image related) from 0 to pi/2.

r=50sin(theta)
r=-15sin(3theta)+35

the two lines intercept at each other at .4256 and pi\2 in the integral.

I have done the first section so really i just need

int{.4256}^{\pi/2} ((1/2)(-15sin(3\theta)+35)^2 d\theta

solved

But my calculator keeps shitting out numbers that are way too big, what am I doing wrong?
>>
>equation in LaTex
>>
>all my math is under the assumption that the area under polar curves is represented as pic
>>
OP: Nvm, figured it out
Thread posts: 4
Thread images: 3


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