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Consider equation [math]a^n+b^n=c^n[/math] for [math]a, b, c

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Consider equation [math]a^n+b^n=c^n[/math] for [math]a, b, c =0,1,2,...,\, n\gt2[/math].
Let [math]a=b=c=0[/math], it's clearly a solution of that equation. Now let [math]a=c=1, b=0[/math], this also solves that equation, so we know there are at least two solutions to that equation, despite the common claim that there are none
>>
>>8940232
>despite the common claim that there are none
[citation needed]
>>
>>8940232
>despite the common claim that there are none
By whom?
>>
>>8940240
>>8940246
Fermat, after whom this equation was named, or Wiles, who got Fields medal for supposedly having proven that this equation has no solutions, even though I've just shown you two
>>
>>8940249
>for supposedly having proven that this equation has no solutions
[citation needed]
>>
>>8940232
>Let a=b=c=0, it's clearly a solution of that equation. Now let a=c=1,b=0, this also solves that equation, so we know there are at least two solutions to that equation, despite the common claim that there are none
But zero is not positive.
>>
ITT I will now disprove the Goldbach conjecture, which states that every even number is the sum of two primes.

Proof: 2 is a counterexample. QED.

Where's my Fields medal bitches?
>>
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>>8940261
here's a counterproof: 1 is a prime number
>>
>>8940249
>Fermat, after whom this equation was named, or Wiles, who got Fields medal for supposedly having proven that this equation has no solutions, even though I've just shown you two
I see no evidence for that...

I also think the formulation that problem was "Integer solutions", which clearly excludes 0.
>>
>>8940261
[math]2=2+0[/math] and [math]0[/math] is prime since it doesn't have any factor save [math]1[/math] and itself
>>
>>8940279
Since when 0 isn't integer? It's clearly not a natural number, but it certainly is an integer
Thread posts: 11
Thread images: 2


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