Failing senior need to pass algebra 2 eoc tomorrow. Anyone

>>8881641
The set of fields between K and F and the set of subgroups of Gal(K/F) are in bijective correspondence.

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>>8881654
Ah thanks ill remember that

>>8881641
just think how prepared you'd be if you'd have spent as much time studying / doing homework exercises as you had spent on 4chan

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>>8881691
>>8881641
You should also understand that A is always congruent to B with respects to a modulus (A-B) or a modulus (B-A)

>>8881654
Show that it is bijective

>>8881641
Follow the logical concatenation of symbols.

>>8881641
y = y

log(y) = log(y)

>log(1) = 0, thus:
log(y) + log(1) = log(y)

y + 1 = y

>>8881722
missed a step
log(y) + log(1) = log(y)
log(y*1) = log(y)
y * 1 = y

>>8881897
>log(y*1) = log(y)
>y * 1 = y
but
log(y*1)=log(1)*log(y)
log(1)=0, thus
log(y*1) = 0*log(y) = 0

>>8881654
This is my favourite theorem in all of mathematics so far, it's such a beautiful surprise

I think Im banned

What algebra ii?

Are you a high school senior who can't pass quadratic equations, rational root theorem, and circles, or a college senior who can't pass rings and fields?

>>8882021
you missed a step
log(y*1) = log(y)
log(y) + log(1) = log(y)
log(y) + 0 = log(y)

>>8881641
Is this bait? I took this in 8th grade and got an A.

>>8882021
> log(y*1)=log(1)*log(y)
false, its
log(y*1)=log(1)+log(y)
log(1) = 0, thus
log(y*1)=log(1)+log(y)=0+log(y)=log(y)