Thread replies: 11
Thread images: 5
Thread images: 5
File: vsauce6.png (685KB, 871x605px) Image search:
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685KB, 871x605px
Alright anons, I have a question for you.
You are given a vector equation w*(2v+u), where w=<2,0,1> and v=<1,2,3>. w is orthogonal to u. You must calculate what this is equal to.
Now, you could solve this through vector algebra and get 2(w*v), but this would only give you one answer, no? What if u is orthogonal to v as well? Could you then take the cross product of v and w to get u?
If you cannot do that, please explain why.
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That image is called vsauce6. That leads me to the conclusion that you have at least 5 other pictures. Post them and I might try to solve it
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File: vasauce.png (676KB, 1045x607px) Image search:
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676KB, 1045x607px
>>8880352
I have 8 but only half of them have vsauce in them
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File: vsauce2.png (770KB, 1085x599px) Image search:
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770KB, 1085x599px
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File: vsauce3.png (590KB, 1044x618px) Image search:
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590KB, 1044x618px
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i got 10 but i took the cross product of w and v which creates a vector orthogonal to both w and v. the question has only one condition and that is that w is orthogonal to u, which it is. so given that information you gave this answer is undeniable correct.
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>>8880360
My favorite part isn't always readnig the side videos.
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File: vsauce4.png (457KB, 1069x595px) Image search:
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457KB, 1069x595px
>>8881685
I double checked my math and this is the right answer. The answer is 10 regardless of whether you do vector algebra or cross products. Thank you.
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>>8880346
>w=<2,0,1>
Sorry, I don't answer questions that use retarded notation
Thread posts: 11
Thread images: 5
Thread images: 5