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i'm trying to solve [math]\int x^3+x^4tanx dx[/math] and

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i'm trying to solve [math]\int x^3+x^4tanx dx[/math] and while i don't want to be spoonfed, i can't seem to utilize any identity to subtitute in u and maker it easier. i tried factoring out x^4 but i'd end up with 1/x and get lnx as my du. i'm going to guess that i need to do two substitions, one for x^4 then another for tanx using a v script. is this better?
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>>8828260
Would splitting it up and then using a reduction formula for x^4*tan^n x work??
>>
>>8828260
Use the linearity of the integral, then integrate by parts. But I don't think that second term is trivial at all, so you'd be better advised looking it up.
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>>8828260
I don't know.
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>>8828298
My stewart book shows this in 5.5 though which iz before parts
>>
You can show tanx as something else. Tryusing that trick.
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>>8828363
I'm not sure how then, since I looked it up and the indefinite integral of xtan(x) is something horrid involving a few polylogs.
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>>8828260
>linearity
Split those bitches
>by parts
Reduce order of the stand alone x term
>rince & repeat

Why wouldn't that work?
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>>8828415
It says its not needed. Just to use simple substitution.
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>>8828431
Perhaps using the go-to integration technique will elucidate the substitution needed....
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>>8828438
but i want to do it properly. if i just do it with parts it's going to make using ocams razor harder lator on, which could conflict with the interferon.
Thread posts: 11
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