When you have something like (m^2 -7)/(m^2-23). Do the m^2's

Brainlets off this board

>>8810878
Yes they do!

>>8810885
they cancel and it becomes 7/23

Yes
[eqn] \frac{m^2 - 7}{m^2 - 23} = 1 + \frac{16}{m^2 - 23} [/eqn]

>>8810874
Yes, you can actually prove this using a little calculus.

[math] \lim_{m\to0} \frac{m^2 - 7}{m^2 - 23} = \frac{0^2 - 7}{0^2 - 23} = \frac{ - 7}{- 23} = \frac{ 7}{23} [/math]

If you don't know that that "limit" thing is don't worry. It is a proof technique that allows you to generalize on the values of a variable by making it closer to a specific numeric value while still preserving algebraic properties.

So indeed, those m^2 cancel.

File: 1465105615712.jpg (37KB, 600x600px) Image search: [Google]

37KB, 600x600px

>>8810894

no. something like m^2/m^2 or 7m^2/16m^2 yes. once you add or substract stuff on either side no

>>8811114
Ok, so when you are adding and subtracting, you cannot cancel, but when you are multiplying you can?

>>8810874
ignore all the retards
go into wolf ram alpha and graph it
if its a constant line
>they cancelled
if its a curvy line
>they didnt cancel

dont rely on retards to answer your own questions

>>8811123
yup

>>8811125
also this if you're willing to graph it

>>8811123
Look buddy, everyone here is just meme'ing on you bacause it is actually quite simple, but you need to be willing to just write it out. You will find many math shit to be simple once you write it out, just a protip.

So we have something similar to
[math]\frac{x^2 + a}{x^2 + b}[/math]
Now, you see two x^2 terms ans you think "hey fuck em lets genocide the x's". Hold you horses buddy, not so fast. Remember you will have to the same to "both sides" (here we have division instead of an = sign, but it is kind of the same idea). So, when you divide it out, you will get
[math]\frac{1 + a/x^2}{1+b/x^2}[/math]
Fuck my ass, this did not get rid of it. By this time it is probably a good idea to start knotting a rope and to find a fan to hang yourself.

No, the M's cancel but the 2's are in the exponent. The final result will be (2-7)/(2-23) = (1-7)/(1-3) = 2