why is dividing by a fraction the same as multiplying by its reciprocal?
>>>/sqt/
>>8777590
do complex numbers have reciprocals?
>>8777605
Yes. If z = (a + ib), then the reciproqual is [math](a -ib)/(a^2 + b^2)[/math].
>>8777605
yes
Dividing by a number means multiplying with its multiplicative inverse.
The multiplicative inverse of r = a/b is r^-1 = b/a, since
r * r^-1 = (a/b)*(b/a) = (ab)/(ba) = 1.
>>8777590
it just werks.
>>8777615
I'm math impaired so please help me understand, why is the lower part squared but not the upper one?
>>8777651
multiply them together to get 1
>>8777651
[math] \frac{1}{a+bi} = \frac{a-bi}{(a+bi)(a-bi)} = \frac{a-bi}{a^2+b^2} [/math]
>>8777615
if you're gonna use tex why the fuck wouldn't you use the frac command
>>8777590
dividing 20 by 2 is finding how many 2s fit into 20.
diving 20/2 by 5 is finding how many 5s fit into 20/2, which is the same as how asking how many 10s fit into 20.
[math]\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c} [/math]
>>8777690
Best explanation in the entire thread.
I wouldn't mind being cucked by you.