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please show me a function that is not absolutely integrable but

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Thread replies: 16
Thread images: 4

File: chrislangan.jpg (176KB, 1353x675px) Image search: [Google]
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please show me a function that is not absolutely integrable but is square integrable
>>
>>8764151
[math]|x|^{-1/2} / (1+x^2)[/math]
>>
>>8764175
oops that's the opposite
>>
>>8764151

[math]f : x \mapsto
\begin{cases}
1 \ \mathrm{if} \ x \in [-1,1] \\
\frac{1}{|x|} \ \mathrm{if} \ |x|>1
\end{cases}[/math]
>>
>>8764230

unconditional functions only.
>>
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>>8764767
>unconditional functions only.
>>
>>8764767
unconditinally funny
>>
>>8764767
[eqn] f(x) = \frac{1}{2} \left( \frac{1}{|x|} + 1 - \left| 1 - \frac{1}{|x|} \right| \right) [/eqn]

Which is exactly the same function as >>8764230
>>
>>8764802
Cool, I was thinking on how to rewrite it using the absolute value.
>>
>>8764802
this still is a conditional function
|x| = x if x > 0 else -x
>>
>>8765502
tough fucking luck
>>
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>>8764767
>unconditional functions only
[math]f(x)=\frac{e^{-\frac{1}{x^2}}}{x}[/math]
>>
[eqn] \frac{x}{1 + x^2} [/eqn]
>>
>>8764151
1/n with the counting measure.
>>
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>>8764767

Unconditionnal kek
>>
[math]f(x) = \frac12 \left( \frac{1}{ \sqrt{x^2}}+1-\sqrt{ \left( 1-\frac{1}{\sqrt{x^2}} \right)^2} \right)[/math]

which is exactlye the same function as
>>8764802
Thread posts: 16
Thread images: 4


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