how do I factorise this? x^2(x-2)-x(2-x) the answer is x(x-2)(x+1)

please keep your stupid questions in the stupid questions thread

>>8748174

[math]x^{2}(x-2) - x(2 - x) \\
= x^{3} - 2x^{2} + x^{2} - 2x \\
= x^{3} - x^{2} - 2x \\
= x(x^{2} - x - 2) \\
= x(x-2)(x+1)[/math]

>>8748281
sorry
>>8748297
thanks

x is throughout. Factor x out:
X(x^2-2x -2+x)
X(x^2 - x -2)
Conjugate sentence: (x+a)(x-b) = x^2+ ax - bx - ab
(X+1)(x-2)=x^2 + x - 2x - 2

>>8748297
>>8748326
why would you do either of these
just pull out the common x(2-x) and you're done immediately, don't expand shit like an ape

>>8748332
The first term is x^2(x-2) not x^2(2-x) you dumbfucc

>>8748356
x^2(x-2) = -x^2(2-x)

or you can flip the other one so it looks like the answer he wants

File: Безымянный.png (23KB, 744x380px) Image search: [Google]

23KB, 744x380px

>>8748273
Did i do right, /sci/?

First time doing these outside of KhanAcademy.

>>8748332
this. you guys are brainlets