>believes repeated division of the remainder by two will ever produce a zero
Claim. Let x be a rational number. x/2^n =/= 0.
Proof.
- Suppose x/2^n = 0.
- Then x = 2^n * 0
- x = 0
This also disproves the famous 0,999... = 1 -illusion.
just hide it, guys
>>8624358
This is wrong on so many different levels.
>>8624364
Give proof. Currently my proof is standing victorious, undefeated, shining example of mastery of mathematics. You on the other hand are just yelling like a feeble child.
>>8624385
Ever heard about limits, my boy ?
>>8624389
Careful not to fall for it
>>8624389
Sure, that archaic, pre-civilized, imaginary concept that is incorrect.
>>8624358
>He fell for the 0/0 meme
Claim. Let x be a rational number. x/2^n = 0
Proof.
- Suppose x/2^n = 0.
-Then 1/2^n = 0/x
-Then 2^-n = 0
-Then 2^n = 1/0
-Then 2^n is undefined
Therefore x/2^n = 0 iff 2^n is undefined.
>1/2^n =/= 0 for any n
>[Idk, stuff maybe? :^)]
>therefore 0.999999=/=1
>>8624358
>>8624667
Sage
>A thread died for this