Can a brainlet confirm my suspicion that the there is an error in the computation of this normal field namely |gradient(f)|
or am I retarded?
grad (f) = idf/dx + jdf/dy + kdf/dz so it is right
>>8619306
but how dey dun that |gradient(f)|= 1/6 tho
yeah
n=∂f/|∂f| must have
|n| = |(∂f/|∂f|)| = |∂f|/|∂f| = 1
everywhere
but clearly e.g. at
r=(1,0,0)
the n in the pic has value
n=(1/6)·(4,0,0) and thus
|n|=2/3<1
>>8619311
Oops sorry misread, the absolute value would equal 6 because sqrt (16+16+4)
>>8619316
You're ignoring the variables