Hey /sci/. A level maths student here struggling with part 2 of this question, could someone give me a hand
>>8472648
Take [math]\ln[/math] of both sides.
[math] y = \frac{1}{2}(ln(1+sinx))[/math]
[math]\frac{dy}{dx}= \frac{1}{2}cos(x)*\frac{1}{1+sinx}[/math]
>>8472655
I tried that, and then rearranged for y=ln(1+sinx)/2. Differentiating this to find the same answer as part 1nis where im struggling
>>8472648
I remember hating this when I was going through this. Don't know if it would work or if you've already tried, but have you put it into wolfram alpha?
>>8472664
You already know how to differentiate functions of the form [math]\ln (f(x))[/math], use that along with the chain rule and you're done.
>>8472664
>wolfram alpha
He/she won't have that in the exam.
>>8472677
Obviously, but you can get step by step on there and sometimes just seeing the answer is enough to get to see the steps you need to take to get there
>>8472664
[eqn] e^{2y} = (1 + \sin x) \\
y = \frac{1}{2} \ln (1 + \sin x) \\
\frac{dy}{dx} = \frac{\cos(x)}{2 (1 + \sin x) } = \frac{\cos(x)}{2 e^{2y} }
[/eqn]
you just have to remember to sub back in for 1 + sin x at the end (or in part 1 sub in for y)
>>8472680
OP may have come for hints rather than a direct answer, but you're right, OP may also just want the steps.
>>8472698
Awhh fuck, was it that easy? Thanks man
>>8472698
this
>>8472648
Good luck OP, I got a D in my maths this year and ended up at Kent instead of Southampton.
>>8472762
I got a D in A2 but had an A in AS so it averaged out to a B. A2 math was fucking ridiculous
Your shadow looks like someone in a bunny suit sucking off Pinocchios nose.
>>8473151
lmao how the fuck do people notice that kind of shit