why is it in leibniz notation a second derivative is noted as
d^2y/dx^2
and not
d^2y/d^2x ?
Because d/dx is the operator. When you apply it twice you get what everyone uses.
>>8465388
so it's squaring the operator, which i understand through d^2y, but how is it with respect to x^2? doesn't that imply your variable has to be second order?
>>8465405
(d/dx)(d/dx)=d^2/(dx)^2
There you go.
>>8465405
(d/dx)^2 = d^2/(dx)^2
Now apply y to it and you get d^2y/dx^2
>>8465413
No probs man, we're all learning.