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How would you find the area of the shaded space above the axis

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How would you find the area of the shaded space above the axis but below the curve?
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>>8449173
Lmao
>>
>>8449173
Are you in elementary school OP?
>>
Integrals.

http://wolframalpha.com/input/?i=int+-x%5E2+%2B+4%2C+x%3D-2+to+2&x=0&y=0
>>
>>8449173
Area under function - area under line y=0
>>
Take the derivative.
>>
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I would subdivide it into small squares of a given area and count them. Then repeat the process with smaller ones until I can infer the actual area from the convergence.
>>
"There it is xD"
>>
>>8449181
Grab them by the dx
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>>8449181
>>8449207
You mean dividing by dx?
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>>8449173
with a double integral of course
[eqn]\int_{-2}^{2}\int_{0}^{-x^2 + 4} 1\ \text{d}y\ \text{d}x[/eqn]
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>>8449198
This works. I used tiny triangles and counted eleven minus one third square units.
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Its boundless there is infinite area
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>>8449173
It is boundless there is infinite area
>>
>>8449232
Pleb.

[math] \int 1_{0\leq y\leq -x^2+4} d\lambda [/math] where [math] \lambda [/math] is Lebesgue measure on [math]\mathbb{R}^2[/math]
>>
>>8449173
here ya go op
https://www.desmos.com/calculator/xu9l0gnibu
>>
You're all overcomplicating this. What you do is make a bitmap out of it in paint. You can then plug it into Mathematica, and make a histogram of white versus gray pixels. If you know the overall dimensions of the image, BOOM, there's your answer.
>>
>>8450461
would you include the curve itself as apart of the area?
>>
>>8449198
>>8450461
That's approximation, not solution.
>>
>>8450468
>would you include the curve itself as apart of the area?
course not! integral is muh area under the curve.
>>
>>8449173
2*integral from 0 to 2 of (-x^2 + 4) dx
>>
>>8449173
>above the axis but below the curve
You mean "above the axis *AND* below the curve"
Lrn2and fgt pls
>>
How would you find the rate of change at a point along the curve?
>>
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>>8449197
underrated
>>
>>8449173
engineer here.

first make about 30 copies of the curve on a copy machine using high quality paper. Measure the area and weight of each piece of paper after printing, being careful to tabulate your results in correct order.

Carefully cut out the shaded area and weigh again. Take the weight ratios and multiply by the corresponding area measurement to get the desired metric.

Apply standard statistical methods to determine the precision and accuracy of your measurements.
>>
>>8449173
find zeros
find convex
area of the "hull" - /int^{x_0}_{x_1}f(x)dx

>>8450461
If I would have wanted to find area of a traingle using MC method my result would be of by 8%
>>
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>>8450787
there's no way you're an engineer
there was no mention of dicks in your post

>>8449173
here you go OP
just throw a bunch of random points in there, and compare the total number of random points to the number of random points in the shaded area
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>>8449197
They rediscovered Riemann Sums
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>>8450668
Differentiate for that point
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>>8450846
This is going above and beyond at this point...
Talk about all your problems looking like nails.
>>
>>8450880
my uni didn't require us to show work - it's how i solved all my calc problems. i lost a point on most stuff because i got one of the decimal numbers wrong
>>
>>8450880
Monte Carlo is more like a multitool
>>
>>8450429
>call others pleb
>cant tex
hahaha well memed my friend
>>
>>8449232
I am fucking retarded, studying calc III and spent 5 minutes trying to remember what the double integral represented, thinking it was a prank answer...
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Use a protracter.
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>>8449173
6 < area < 16
>>
Monte Carlo simulation :^)
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>>8450747
how the FUCK did you find that
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>>8450747
Multiplied by 2, dumbass
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>>8449232
>not a triple integral
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>>8449173
you just say its infinite
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>>8449173
substitute your x for e in this equation (see Fermat's Rule for why) and your constant for one of the integrals (Because the dx of x is any constant)
>>
Whoops saged without meaning to
>>
>>8450472
>That's approximation, not solution.

True, but Mathematica shitpost == priceless.
>>
>>8449173
Best homework thread evar.
>>
>>8449197
>Acknowledgments—I would like to dedicate Tai's Model to my late parents Mr. and Mrs. T. C. Tai.

awww :(
Bet they'd be proud!
>>
32/3?

did that in my head

took 7 minutes though
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>>8451680
12
>>
>>8449173
integrate between the roots
\int_{-2}^{2}x^2+4\text{ d}x
>>
>>8449173
integrate between the roots
[tex]\int_{-2}^{2}x^2+4\text{ d}x[/text]
>>
>>8453641
>>8453546
You're a failure, give up on life
>>
>>8453546
>>8453641
fuck im never browsing sci again
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>>8453641
use ["math"] without the quotes
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>>8453703
thx b
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>>8449173
A square plus b square equals see square
>>
2 square plus 3 square equals see square

4plus9equals13...square?
26 26 26 26
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>>8453546
Integrate[-x^2 + 4, {x, -2, 2}]
>>
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>>8453914
>>
>>8449173
>no one mentioned the method of exhaustion
Has /sci/ finally gone full brainlet?
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>>8449173
50%, it either happens or it doesn't
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>>8449173
draw a rectangle around the curve and fill the space around it with infinite triangles, add up the area of those rectangles
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>>8449197
I still can't believe this is real
>>
Find the area of the entire box

Then subtract from it the area outside of the shaded regionf
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>>8450846
that worked really well, probabilistic methods are neat
>>
>>8453641
delet this
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>>8450570
"But" is LITERALLY the exact same fucking thing as "And" logically speaking.
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>>8449173
[eqn]\int_{-2}^{2} (-x^2 + 4)\, dx = \left[ \frac{-x^3}{3} + 4x \right]_{-2}^{2} = \frac{-8}{3} + 8 - \left( \frac{8}{3} - 8 \right) = 16 - \frac{16}{3} = \frac{32}{3}.[/eqn]

Now fucking KYS and never come back
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>>8449197
This only works for glucose tolerance and other metabolic curves, you retard :^)
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>>8449197
>Mary
fugging wymmyn amirite
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>>8449197
http://www.math.uconn.edu/~kconrad/math1132s14/handouts/taicomments.pdf

She responded to some comments in this
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>>8454054
The voice of reason has spoken
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>>8454054
>using jewish integration
top kek, JIDF pls go
Thread posts: 74
Thread images: 8


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