Is [math]0 \geq x > 2[/math] the negation of [math]0

>>8449088
no.
[math] 0 \geq x [/math] or [math] x> 2 [/math]

>>8449100
This.
>>8449088
Read up on DeMorgan's laws. [math]0 < x \leq 2[/math] is shorthand for [math]0 < x[/math] AND [math]x \leq 2[/math]. Your answer is wrong, OP, because it can't be the case that x is both less than 0 and greater than 2.

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>>8449100
That's not negation, that's the complement.

I'd say the answer is [math]-2 \leq x < 0[/math]. That is, the negation of [math]x \in (a, b][/math] is [math]x \in [-b, -a)[/math]. This is nice, because if [math]x[/math] can only have one value, then the negation is [math]-x[/math] like it should be.

>>8449110
>literal autism the post

>>8449110
bait

>>8449100
This is the right answer from the logic point of view.

>>8449110
This is the right answer from the interval arithmetic point of view.