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Can you guys help me with my home work? A random polynomial P(x)

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Can you guys help me with my home work? A random polynomial P(x) is given. When the limit of P(x)/[x 2-4] tends to infinity it equals 4 when it tends to 2 it equals 9/4. I gotta find the polynomial P(x).
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X 2 is supused to be square x
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And in the last lim of the pic it's supposed to tends 2 not infinite
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The numerator has a 4x^2 term
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>>8431710
Why?
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>>8431721
Because of the limit to infinity. It means that at infinity, the limit is equivalent to 4x^2 / x^2 which then is equal to 4.

Not only do you know it has a 4x^2 term, you also know that is the leading term because if it has a bigger term (like an x cubed) then the limit would diverge to infinity.
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>>8431696
You can factor the denominator into (x-2)(x+2), what does that mean for the convergence at x=2 and P(x)?
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>>8431732
I somehow got to simplify x-2
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>>8431727
Oh thanks my dude now i undrstand
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>>8431732
It should be like something*(x-2) and that something for P(2) should be 9
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Lim x -> inf of P(x) / (x^2 - 4) = K

Apply Lhopitals rule twice and reason P(x) has to be polynomial of degree 2.

P(x) = Ax^2 + Bx + C
P'(x) = 2Ax + B
P''(x) = 2A

x^2 - 4

2

2A/2 = K

A = K

SO P(x) = Kx^2 + Bx + C where B and C can be any number you want.
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>>8431752
I know it's degree is 2 by now but i am asked what's the polynomial P(x)
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>>8431696
>Can you guys help me with my home work?
no
>>
P(x) = Kx^2 + Bx + C where B and C can be any number you want.

K is the number the limit is equal to.
>>
Ok thx guys you are the best i've solved it
Thread posts: 15
Thread images: 1


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