I know this be taken as a homework request, but it isn't

Integral calculus

>>8340113
Look up the 5 kinematic equations and look for v_f = v_i + a*t

>>8340113
I think you need calculus to solve this, or it makes it much easier, since acceleration varies with time. You can't use your regular kinematic equations since those assume constant acceleration.

What you need to know is that acceleration is the derivative of velocity, so all you need to do is find the equation of the curve in your pic, then integrate from 0 to 3. A more simple way is to know that an integral gives you the area under the curve, so all you need to do is find the area under the red line. Hint: It's a trapezoid.

>>8340113
You could either find the area under the curve by splitting it into a rectangle and a triangle... Or you can use v = v0 + at with v0=0 and a =2 and t =3

>>8340113
Calculus problem you can solve with geometry.

Calculate the area of the trapezoid formed by the red line, and the "a" and "t" axes. You could do this by dividing up the shape into two: a square and a triangle. Add up the two areas and you have your velocity.

>>8340121
>>8340143
You can't use kinematic equations for non-constant acceleration.

File: durrr.jpg (16KB, 351x329px) Image search: [Google]

16KB, 351x329px

>>8340151
my b forgot havent done physics since hs xD

Thanks goys!

>>8340113
[math]\int_{0}^{3}{\frac{1}{3}x+1 dx}[/math]
as
[math]v = \frac{dv}{dt}\\and\\a = \frac{d^{2}v}{dt^{2}}[/math]

[math] \displaystyle
position \; \frac{ \overset{/time}{ \rightarrow}}{ \underset{ \texttt{x} \, time}{ \leftarrow}} \; speed \; \frac{ \overset{/time}{ \rightarrow}}{ \underset{\texttt{x} \, time}{ \leftarrow}} \; acceleration
[/math]