Pretty sure 90% of sci can't tell if the asymetric carbone

R

S

>>8258137
It's a 50/50

Request proof

R

S

R - longest carbon chain

>>8258153
Not how it work imo

>>8258117
1 - oxygen of carbohydrate thingy
2 - carbon, neighbour of which has two methyl groups
3 - carbon, neighbour of which has one methyk group
4 - hydrogen ofc
1-2-3 -- clockwise
therefore, R

Long time since I've done these but I'll have a go. Priority one is the ether, two is the lower part of the ring, I think the C terminus of the enone is higher priority than the quaternary carbon in the upper part. Leaving the upper part as priority 3. The hydrogen in the rear makes it anti-clockwise and hence S. I could be wrong but that is my reasoning.

>>8258207
Why did you put 2 and 3 in this order? Can you draw the tree

1-4 are easy

>>8258220
priority is determined by atomic number(or mass), of they are the same, checks sum of atomic numbers of its neighbours, if it's the same, check sum of its neighbours' nighbours
#2 has a neighbour that has two methyl groups, contrary to #3, neighbour of which has only one, making

>>8258219
Op here. It's R. You confused 2/3

>>8258220
>>8258230
>cont'd
oh and #4, that is the lightest group must be contained in the back

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2MB, 2448x3264px

>>8258230
Yes but it has a double bond, that count as a ghost carbon? Can't we continue on that ghost one?

Pic related.

>>8258245
in all my years I've never hear of "ghost" carbons
I was taught the way I explained above

>>8258207
>>8258230
this is the right answer and for the right reason. thread over.

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>>8258251

and then we all remember this is all a meme and the only time it ever matters is on a midterm test.

>>8258918
well in that case the molecule would be considered as symmetrical and no R,S would apply