I was reading a thread that said "a proposition and its

well everyone in new york IS gay, so...

>>8001005
>because either everyone in New York is gay or not

Right, so they can't both be false.

>>8001008
Ted Cruz, pls go

Your question was adressed n that thread, ehy make a new one?
(You also quoted it wrong, why not make a direct quote?)

>>8001005
The logical negation of "everyone in New York is gay" is "there is someone in New York who is not gay".

http://faculty.simpson.edu/lydia.sinapova/www/cmsc180/LN180_Gersting/L06-NegationQ.htm

>>8001445
I think you mean there is at least someone in New York who is not gay.

>>8001481
>>8001445
which is what OP said if only you could read. (he said "not everyone is gay", he didn't say "everyone is not gay")

>>8001495
I think OP is confusing the logical conjunction 'and' with the grammatical conjunction 'and'. In this context 'and' implies both propositions being false at the same time, not their intersection being false.

>>8001495
Yeah but I don't think the OP understood what he wrote is equivalent to that.

>>8001521
I think he understood that fine, he's just misinterpreting what 'and' means in this context. The conjunction of a true statement and a false statement is always false.

>>8001538
The fact that the OP says "because either everyone in New York is gay or not" makes me think otherwise.

>>8001551
He means, either everyone in New York is gay or not everyone in New York is gay. In other words, one of these must be true and the other false, therefore their conjunction is false.