If you roll a pair of dice, what are the odds that a second pair

>1/6

>>7993947
For one die, yes
But what about two? In the picture posted both dice need to match the original pair. A friend is arguing that it's 1/3x1/6 because the first die can match either of the two original dice, but that doesn't seem right to me. I'm really shit at math so I thought I'd ask people that actually like it

>>7993943
Well it depends on how your question is interpreted, I think what you're saying is if you have four dice and role them in pairs. I'm which case I'd say that it was 1/36, you don't really care about what the first set dice come up, but just that the second pair role the same.

File: 1397766697757.jpg (44KB, 393x450px) Image search: [Google]

44KB, 393x450px

>>7993956
Thanks friend

>>7993956
there aren't 36 unique pairs of dice though if you aren't counting the order of them (which OP presumably isn't)
there are only 21

You have 36 combinations for a pair of 6 sided dice.

1:1
2:2
3:3
4:4
5:5
6:6
Appear only once while things like 2:1 and 1:2 effectively are the same thing so you get.

Effectively if you first roll anything that isn't dubs you have 2/36 chance. If your first roll is dubs you have only 1/36 chance.
6/36 * 1/36 + 30/36 * 2/36 = 0.05092592592 = 5.09%

Pretty shitty.

>>7993974
moron

>>7993943
1/21

In your scenario, only the total matters

>>7993999

If only the total matters, then it depends on the first roll

There are more ways to roll a 7 than there are to roll a 2

>>7993999
You are a fucking moron. If it's actually total then your answer is also incorrect.

>>7993974
This.

You have a 5/6 chance of rolling two distinct numbers, with a 2/36 chance of the second pair of dice matching them; or a 1/6 chance of rolling two equal numbers, with a 1/36 match chance. Total match chance is 5/6*2/36 + 1/6*1/36 = 11/216 which is approximately 5.09%.

You guys are fucking retarded. It's 1/21. There are 21 different combinations and they're all equally likely to occur.

If it's just total number then:

There are 6 ways to roll 7, 5 ways to roll either 6 or 8, 4 ways to roll either 5 or 9 and so it goes up to 2 or 12 where there is only 1 way to roll either. We can shorten it to 2 *(1^2 + 2^2 + 3^2 + 4^2 + 5^2 + (6^2)/2)/(36*36).

Around 11%.
>>7994042
Prove it.

there is probably a slightly greater chance of getting a 6 due to it being the lightest side

>>7994052
1,1-6 ->6
2,2-6 ->5
...
6,6 -> 1

6+5+4+3+2+1 = 21

Obviously it's not asking for the total to be the same, it's saying the result of the two dice should be the same.

>>7994084
If you take two dice with 2 sides as an example then you get
1:1
2:1
1:2
2:2
As possible combinations. What you are effectively doing is merging the two in the middle into one and saying you've got 1 in 3 chance of winning. It's equal to having 1 black ball, 1 white black, 98 balls of various faggot colors and then merging all the colored ones into 1 option and saying you've got 1 in 3 chance of rolling a faggot ball.