How much power does a led emitting 6000 mcd of 465 nm blu light

Anyone has some advice?

Just give me an advice

Please

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https://en.wikipedia.org/wiki/Candela#Explanation
<--wavelength dependent formula

>>7809043
According to my math, one of these leds https://www.adafruit.com/products/301 outputs only 0.01 W. Is this even possible?

>>7809811
yes, most commong 5mm leds are 0,01W/0,25W/0,6W/1W

>>7809818
Are you talking about the power they use or about the power they output?

>>7809825
if you tried to integrate the emitted wavelengths to find out the power it emits 0,01 sounds like a reasonable result.

>>7809867
just write down or screencap what you're trying to find out and i'll help. also post a pic of your calculations

>>7807680
>I don't know how to calculate that for blue light.
It's not a calculation; light follows aberrant quantity rules. Detection depends on the composition of the measuring body, wattage inclusive.

>>7809887
I'll explain everything:
According to this paper ( http://emedicine.medscape.com/article/1894477-overview#a4 ) I need 10 mW/cm^2 of blue light at 458 nm (I found those 465 nm blue led: https://www.adafruit.com/products/301 ), over an area of 0.10 m^2 (30 * 30 cm).
Now I can't tell how many leds would I need to get those 10 W.
If every single of those leds output 0.01 W I'd need 1000 of them, but that seems overkill.
Anyway this is how I calculated it:
6 cd / (683 * 0.1).
I got the last number from this site ( http://www.cvrl.org/lumindex.htm ) for 465 nm light.
That gives me 0.1 W/sr.
In the leds vendor page the viewing angle is listed to be 20 degrees (10 + 10).
So it covers a solid angle of (assuming a sphere of radius 1): PI * (sin 10°)^2 / (1^2), which is 0.1 sr.
It follows that the total power that a single led emits is 0.1 W/sr * 0.1 sr = 0.01 W.
Did I get it wrong?

>>7809894

>>7809043

Help?

>>7810365
Me!

>>7809927
i tried this for 555nm and checked with this website to make sure i did everything correct.. then i did the same calculation for 480nm and i got 0,012W which is either correct or we are both idiots. http://www.translatorscafe.com/cafe/EN/units-converter/illumination/9-11/lumen%2Fcentimeter%C2%B2-watt%2Fcentimeter%C2%B2_%28at_555_nm%29/

>>7811317
:( please

>>7811703
Thank you, for some reason it didn't show me your reply. That is a lot less than what I was hoping.