What is the answer to this equation, not using a calculator or Google
20/2(5+5)?
Pic unrelated
20/2(5+5)
20/2(10)
10 * 10
100
(5+5)=10
20/2=10
10*10=100
>>7784355
20/2=10
10(5+5) = 50 + 50
50+50=100
Im gay
20/2(5+5)
20/2(10)
20/20
1
20/2(5+5)
first:
2*5+2*5=20
20/20=1
easy.
>>7784459
>2*5+2*5=20
Tell me how?
1. Parentheses go first, the operation inside of them is a different matter.
20/2(5+5)
100/2+100/2
50+50
100
>>7784355
20 / 2(5 + 5)
20 / 2(10)
20 / 20
1
>1
Ishygddt
>>7784355
100
20/2(5+5)
20/10+10
2+10
12
always remember your distributive propertys
>>7785811
Pls be troll. 1 or 100 are valid arguments, depending on interpretation (100 is right though), any other answer is right out
>>7785832
? first you distribute the 5 into the parentheses and then they break apart. then you have 20/10+10
division goes first because pemdas and then you get 12
>>7784355
The problem is stated poorly. 100 is technically correct by modern conventions but no one who actually knows what they're doing would write something as potentially misleading as "20/2(5+5)".
>>7785879
This.
/thread
>>7785879
Yep. Let's end these threads.
20/(2*(5+5))
20/(2*(10))
20/(20)
1
100 is incorrect, anyone who put that is a troll and this is a meme.
>>7784355
PEMDAS?
20/2(5+5)
20/2(10)
20/20
1
???????? Tell me if I'm wrong and why.
>>7784459
You would have to distribute 20/2 into (5+5) yielding (5*20/2 + 5*20/2)
Or (100/2 + 100/2)
Or (50 + 50)
Or (100)
>>7784481
He's one of the type that think distribution is part of the parentheses step
>>7788398
Division comes before multiplication, so from
20/2(10)
10(10)
100
20/2(5+5)
ln(5+5) = 2.303
2.303*5 = roughly 10
ln 10 = Varys kills Pycelle & Kevan
Answer = 1
[math]20/2(5+5)=20/2(10)=\frac{20}{2} \cdot 10=10 \cdot 10 = 100[/math]
Parentheses first, then division and multiplication on the same time from left to right, then subtraction and addition from left to right as well.
>>7784355
20/2(5+5)
20/2(10)
20/20
1
>>7785879
+100
>>7788789
Division/multiplication is done left to right.
Only noobs who don't know that there are at least 2 algorithms to solve these questions will answer or ask this kind of retarded question.
1. Shunting yard algorithm
2. Pemdas/watever u wanna call it