/sci/ this probably isn't the place for homework but I'm

>>7671250

baka desu, you aren't solving for ohm it's given

Which equation are you using for power? The most intuitive one is I^2*R, since V for the power equation means voltage across the individual resistor.

>>7671284

OP didn't read the question and anon didn't read the OP. /sci/ is literally the retards leading the blind. Fuck this place.

>>7671277
Oh shit I mean between 1.2 and 1.4 Watts, my mistake

>>7671284
I calculated .8 A for my current through resistor 2

(.8)^2 * 2 = 1.28, which was wrong apparently

>>7671300

Yeah you're making a bonehead mistake somewhere, go work on it some more, this is baby shit anything less than 2 W is definitely wrong.

>>7671250
r1 = 5;
r2 = 2;
r3 = 4;
r4 = 1;
v = 24;

A = [(-r1-r3), -r2, 0; 0, r2, -r4; 1, -1, -1];
b = [v; 0; 0];

I = A\b;

the answers your missing are:
r2*I(2)^2
and
r4*I(3)^2
you're close maybe just rounding error

>>7671250
Calculate total current I, use I^2*R to find P_5Ω and P_4Ω
1/3 of I flows through 2Ω and 2/3 of I flows through 1Ω
Use (I/3)^2*2Ω to find P_2Ω and (2I/3)^2*1Ω for P_1Ω

>>7671373
r2*I(2)^2 = 1.369797859690844
r4*I(3)^2 = 2.739595719381688

>>7671284
So what is dP/dR? R or 1/R?
:^)