sci, i do not understand what's going on there [math]\[\frac{x+\sqrt{x^{2}-1}}{x}\

>>7667495
[eqn]\[\frac{x+\sqrt{x^{2}-1}}{x}\] [/eqn]

>>7667499
[math]\[\frac{x+\sqrt{x^{2}-1}}{x}\][/math]

>>7667501
[math]$\[\frac{x+\sqrt{x^{2}-1}}{x}\][/math]

File: CodeCogsEqn.gif (839B, 224x45px) Image search: [Google]

839B, 224x45px

>>7667502
MOTHER FUCKER

>>7667506
are you retarded?

wtf happened to writing jsmath equations on this site?
It's been broken for about a month now.

>>7667700
>>7667506
seconding, can you really not see how that works? lol

>>7667754
do you consistently check if your code works in your texeditor?

>>7667506
Factor out [math]x[/math] from the radical.

Divide 2 terms by [math]x[/math].

[math]\sqrt{x^2 -1} = x\sqrt{1 - \frac{1}{x^2}}[/math]

>>7667811
let's see if this works,
if it doesn't work all the raw code
including math and slashmath
are just shown instead of being interpreted:

[math]1+\frac{1}{2}=\frac{3}{2}[/math]

>>7667811
i was wonder more like how to simplify the leftmost expression here >>7667506
to get the right most one

>>7667506
>>7667700
>>7667794
obviously in 8th grade and put in too high a math class

>>7667796
>if it doesn't work all the raw code
>including math and slashmath
>are just shown instead of being interpreted:

[math]1+\frac{1}{2}=\frac{3}{2}[/math]

[eqn]1+\frac{1}{2}=\frac{3}{2}[/eqn]

>>7668134
honestly i'm missing something here


how do we get from

[eqn]\frac{\sqrt{x^2 -1}}{x} [/eqn]

to

[eqn]\sqrt{1 - \frac{1}{x^2}}[/eqn]

do a right click on the equation, copy the tex code of the equation, put it in eqn tags and it works

>>7668151
x = sqrt(x^2) right? put that in the denominator and take it from there champ.

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>>7668158
god i feel stupid

thank you

Dude, just divide by x you scrub

>>7668166

hey man, at least you didn't ask how x / x simplified to 1 :^)

i have more questions...

[eqn]\frac{x^2+xln(x)}{x+1}[/eqn]

how does it reduces to

[eqn]\frac{x^2(1+\frac{lnx}{x})}{x(1+\frac{1}{x})}[/eqn]

>>7668881
how does it reduces to

[eqn]\frac{x^2(1+\frac{lnx}{x})}{x(1+\frac{1}{x})}[/eqn]


>preview displays correctly
>posts doesn't

why

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10KB, 138x103px

>>7668881
>how does it reduces to

>>7668133
That's essentially what he showed you.

>>7668955
yeah i realized as i posted that there was factorisation going on there

>>7668890
They just factored the top and bottom.
You really can't be old enough to post here.

>>7668885
It's the way 4chan parses the TeX, you need to throw in white space errywhere near all the commands. Now lets see if I can do it without looking like a tool: [eqn] \frac{x^2 \left( 1+ \frac{ \ln(x) }{x} \right)}{ x \left( 1 + \frac{1}{x} \right)} [/eqn]

There's a neat little theorem I came up with that relates to this subject. Let f(x) be an invertible function.
Then a*f(x) = f(f'(a)*x), where f' is the inverse of f(x).
It's essentially what you do when multiplying x with sqrt(x): f'(x) = x^2 and then it works

>>7669184
f(x)=x+1
a*f(x)=ax+a != f((a-1)*x)=ax-x+1

Not op here. I swear.

I have an issue in the same vein as OP's. How do i go from this

[eqn] \frac{ xlnx }{ \sqrt{ x } } [/eqn]

to this

[eqn] \sqrt{x} * ln x [/eqn]

>>7669457
You learn grade school algebra you fucking dumbass.

>>7669457
x/sqrt x=sqrt x
or for retards
x/sqrt x=x*x^(-1/2)=x^(1-1/2)=x^(1/2)=sqrt x

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>>7669466
>>7669463