Robots, you guys are smart, could you explain how to solve this

>>36042235
two eighty

>>36042273
Don't meme at my struggle

360-130

230

Where is that 360 from

its probably a circle

>>36042495
Meant for >>36042447

Originally phoneposting

>>36042495
the full circle that the shape makes

>>36042515
Does it?
You can't trust the shape only the values and you weren't given any values of have to find them first

>>36042235

http://www.gmatquantum.com/blog/revisiting-angles-of-a-star.html

Im lazy to calculate the solution but here it is. Also, OP's star suffer from autism.

>>36042657
>OP's star suffer from autism


That's partially what's confusing me I think
Because the thing might look like a star but I don't know if it's actually one because I don't know if/which lines are parallel and shit
Or even if that matters
Goddamn I hate geometry

>>36042235
Your pentagon approach was correct.
The inside angles of a pentagon add up to 540 because (n-2)*180 where n is the number of sides.
The two sides of a triangle = 180 - the other side.
Therefore 540 = 5*180 -a -b -c -d -e -(20+30+10+30+40)

a+b+c+d+e=230

>>36043036
>>36042447

originally
told you

>>36043036
The answer is supposed to be 360

There was also a "490" written near this exercise (from someone else who had already solved it) and 490 - 20 - 30 - 10 - 30 - 40 = 360
But where did they find 490 from

>>36043309
Oh yeah, you're right
it should be a+b+c+d+e =180*5 - (sum of the opposite 2 angles for a,b,c,d,e + 130)
so it becomes a+b+c+d+e =180*5 -540

Idk about a 490

Solve for each triangle.

>each pentagon angle is 108
>both sides are (108-angle)/2
>triangle and surrounding angles are:
>40 34
>20 44
>30 39
>10 49
>30 39

a is 180-34-44=102
b is 180-44-39=97
c is 92, d is 92, e is 107

a+b+c-d+e=490

>>36043551
>>36043552


What horrible fuckery

Thanks guys

File: Math.gif (1MB, 320x180px) Image search: [Google]

1MB, 320x180px

>>36043868
we are not clever men

>>36043552
Was the dividing by 2 necessary?

>>36042235
Bout tree fiddy
trust me

>>36043552
Or alternatively a pentagon has an angle sum of 540 subtract the star angles (20, 30... Etc), A triangle has 180 degrees, multiply 180 with the amount of triangels you have, then subtract the earlier sum from that, and you will have the sum of a+b+c+d+e

>540 - 20 - 30 - 10 - 30 - 40 = 410
>180 * 5 = 900
>900 - 410 = 490