First, we must determine the LD50 (lethal dose for 50% of th

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First, we must determine the LD50 (lethal dose for 50% of the population) of Zyklon B (HCN): for 1 min inhalation in a rat, we find that to be 1471mg/m^3. - https://webwiser.nlm.nih.gov/getSubstanceData.do?substanceId=38&displaySubstanceName=Zyklon%20B&STCCID=&UNNAID=&selectedDataMenuItemID=78

Next, we need to convert the units of mg/m^3 to mg/kg, which we will use for a later calculation. - https://pubchem.ncbi.nlm.nih.gov/compound/hydrogen_cyanide#section=Vapor-Density

Air is given as a reference equal to 1, with a value of 1.223kg/m^3. HCN is given a value of .94.

1.223 * .94 = 1.15mg/kg

1471mg/m^3 * 1m^3/1.15kg = 1279mg/kg

Now we must use a dosing calculator to convert from animal to human. - https://www.ncbi.nlm.nih.gov/pmc/articles/PMC4804402/#!po=57.4074

Using the Animal dose to the Human dose using a human as 60kg and a rat as .5kg (http://web.jhu.edu/animalcare/procedures/rat.html)


Human Dose = 1279mg * (.5/60)^(1-.67) = 263mg/kg

Multiplying this dose by the body weight of 60kg, we get a value of 15800mg, or 15.8kg