works: #!/bin/bash if [ $BASH_VERSION = "4.4.12(1)-release"

>>61062712
[ is the name of a binary
[$BASH_VERSION is not

Bash is not a programming language, stop using it as such.

>>61062780
by binary, do you mean a boolean value, or an executable?

>>61062861
An executable

$ whereis [
[: /usr/bin/[ /usr/share/man/man1/[.1.gz

"[" is actually a program, it's alias for "test", would recommend watching
https://www.youtube.com/watch?v=olH-9b3VJfs
(website http://shellhaters.org/)

File: 878160.png (187KB, 450x450px) Image search: [Google]

187KB, 450x450px

>>61063133
>>61063187

thx guys.. sorry i called you bashtards

>>61062712
it works on my machine

#!/bin/bash

if [ $BASH_VERSION = "4.4.12(1)-release" ]
then
    echo "BASH VERION: 4.4.12(1)-release detected"
fi

>>61063133>>61062780
That's incorrect though. The command [ calls a bash builtin normally.

>>61063469
the key to getting it to fail is removing the whitespace after the [

i watched this --->>>61063187

it cleared it up very well.

File: 2a2e5cd5bc8f848e44b5e56cb6a12b11b3f83f56.png (93KB, 412x516px) Image search: [Google]

93KB, 412x516px

>>61063187
21:17
C-x C-e

Ho my gosh, i didn't know that trick. I didn't regret watching that video.

>>61062780
what the fuck, I never knew that. maybe because I avoid bash at all costs

>>61063518
[[ is a bash builtin. [ is an executable.