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Does anyone know MIPS assembly? How do i remove any leading

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Does anyone know MIPS assembly?

How do i remove any leading and trailing zeros from a number?

I am learning about loading and storing bytes.

given a number like 000011, or 001111000, or 11100, I have to print it without the leading/trailing zeros

ex: 0011100 -> 111

the numbers are stored in a buffer " .space 20 "

what I have done so far is starting from the right side of the number 001100, find the first nonzero number and then store the rest of the numbers to a new buffer.
number is now: 1100
Then from the right side of the new number, find the first nonzero, and store the rest to a new buffer.
number is now: 11

BUT the problem is if i print the new buffer,it will still print out trailing zeros because the buffer is too big.

how do I make a buffer just big ENOUGH to fit the number without the zeros?

am i overthinking this? Is there a MIPS function or shortcut that can do this for me?

please help!

thanks!
>>
>>59202929
I don't know MIPS. But I know C.

And the solution would be:
- if it's a 32bit val 00011100, identify the offset to the first 1, and then bitshift it left e.g. 00011100 << 3 = 11100000
- if it was a string "0011100", move the pointer -3, "111000"
>>
>>59202929

https://www.cs.umd.edu/class/sum2003/cmsc311/Notes/Mips/bitshift.html

thank you for contacting /g/ - homework help
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