>it says here that you can't do fizzbuzz without if else

>>56490928
kys?

10 print "fizz"
wait 4
beep
print "buzz"
goto 10

>>56490955
fortran?

>>56490928

switch...

File: fizzbuzz_of_the_christ.png (402KB, 1024x768px) Image search: [Google]

402KB, 1024x768px

You mean like this one?

>>56490928
Easy, I lack experience.
That'S why I code in my free time, too.
So could you please leave me alone, so I can continue being a miserable pile of secrets?

./fizzbuzz.sh

>>56491012
Looks like basic desu senpai
i can tell from some of the pixels and the fact that print statements aren't formatted like that in fortran

>>56490928
How long has she been on HRT? I want to be a tech emo girl too.

>>56490928

(defun shiggylicious (n)
  (dotimes (i n)
    (format t "~%~:[~d~:;~:*~{~c~^~}~]"
      (append (and (zerop (rem i 3)) (coerce "fizz" 'list))
              (and (zerop (rem i 5)) (coerce "buzz" 'list)))
      i)))

File: her shey.jpg (105KB, 1000x1000px) Image search: [Google]

105KB, 1000x1000px

>>56491449
>she
>girl

>>56491543
I'd totally cover her dick in hershey's and suck on that feminine penis

>>56490928

# include <stdio.h>

int main ( ) {
    int i=0;
A: ++i;
  if (i - (i/3)*3 != 0)
  {
      goto B;}
  printf("Fizz");
B: if (i-(i/5)*5 != 0)
  {
      goto C;}
  printf("Buzz");
C: 
  if (i-(i/3)*3 !=0 &&  i-(i/5)*5!=0)
  {
      printf("%d", i);}
  
  printf("\n");
  if (i<100)
  {
      goto A;}
 }  

>>56490928
I can do it just with if statements.

>>56491563
You're using if else
>>56491661
Heh

x=cellstr(int2str((1:100)'));
x(3:3:end)=cellstr('Fizz');
x(5:5:end)=cellstr('Buzz');
x(15:15:end)=cellstr('FizzBuzz');
fprintf('%s\n',x{:});

>statement
EVRYTHING IS AN EPXPRESSSION YOU WHORE

public static void main(String[] args){        
        for(int i = 1; i <= 100; i++){
            String test = "";
            test += (i % 3) == 0 ? "fizz" : "";
            test += (i % 5) == 0 ? "buzz" : "";
            System.out.println(!test.isEmpty() ? test : i);
        }
    }

>>56492215
That's literally just a shorthand if else statement.

switch (i % 3) {
    case 0: {
        switch (i % 5) {
            case 0: {
                // Fizzbuzz
            }
            default: {
                // Fizz
            }
        }
    }
    default: {
        switch (i % 5) {
            case 0: {
                // Buzz
            }
            default: {
                // Number
            }
        }
    }
}

Just use a visitor design pattern.

#include <stdio.h>

static void num (int n) { printf("%d\n", n); }
static void fizz () { printf("Fizz\n"); }
static void buzz () { printf("Buzz\n"); }
static void fizzbuzz () { printf("Fizzbuzz\n"); }

int main (int argc, char *argv[]) {

    void (*fp[4])(int n) = {num, fizz, buzz, fizzbuzz};

    for (int i = 1; i <= 100; i++) {
        fp[(!(i % 3)) + ((!(i % 5)) << 1)](i);
    }
    return 0;
}

>>56490928
How big is Pistol's pistol?

>>56491402
That's actually pretty cool. Forgot you could do that range selection in Python.

for i in xrange(1,100): print 'FizzBuzz'[4*(i%3>0):8-4*(i%5>0)] or i