(QUICK (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT

>>55639777
#algorithm
#0. Copu and convert the whole input into a string
#1. Index the '(''s
#2. Find the last one
#3. Return a string until the first ')' is reached

>>55639828
Copy*

File: STABBING INTENSIFIES.png (364KB, 416x430px) Image search: [Google]

364KB, 416x430px

>>55639828
THAT'S NOT YOUR FAVORITE LANGUAGE

>>55639777
>

(UNDER A (RANDOM CHARACTER POSITION)))

what did he mean by this

>>55640063
a random number from 0 to post.length

>>55639990
BIRDMIN NO

>>55639777

Hey Vrajesh, go write a program that does this

my favorite language is english.

i still don't get it

File: STAB.png (271KB, 416x430px) Image search: [Google]

271KB, 416x430px

>>55640117
[X] STAB

>>55640160
I guess you have to parse the grammar

E : '(' E ')' | '(' ')' | [a-z]+ E | [a-z]+

or something, and store the offsets in the nodes.

>an interesting knifebird challenge for once
Nice

>>55639828
>>55639828
last '(' doesn't have to be the innermost one.

>>55640212
>>55640160
>>55640063
When given 0, it should return the whole post.
When 1~5, it should return QUICK.
When 14, 16 or 24 it should return (A PROGRAM).

>>55640259
Yeah, you got a fair point

File: dontstabme.png (15KB, 979x514px) Image search: [Google]

15KB, 979x514px

>>55639777
>>55640280
didn't quite understand the description in the op, is this it?

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char* get_word(char* s, int start) {
    int i = start + 1;
    while (s[i] != '(' && s[i] != ')' && s[i] != ' ' && s[i] != '\0')
        i++;
    char* word = malloc(i - start + 1);
    strncpy(word, s + start, i - start);
    word[i - start] = '\0';
    return word;
}

char* get_expression(char* s, int start) {
    int i = start + 1;
    int depth = 1;
    while (s[i] != '\0') {
        i++;
        if (s[i - 1] == '(')
            depth++;
        else if (s[i - 1] == ')' && --depth == 0)
            break;
    }
    char* expr = malloc(i - start + 1);
    strncpy(expr, s + start, i - start);
    expr[i - start] = '\0';
    return expr;
}

int main(int argc, char* argv[]) {
    if (argc != 2) {
        printf("Missing position argument\n");
        return 1;
    } 

    int pos = atoi(argv[1]);
    char* result;
    char* text = "(QUICK"
                 " (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT"
                 "  (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))"
                 "  (UNDER A (RANDOM CHARACTER POSITION)))"
                 " (OR (THIS BIRD) IS GONNA (STAB YOU)))";

    switch (text[pos]) {
        case ')':
        case ' ':
            while (text[pos] != '(' && text[pos] != '\0')
                pos--;
        case '(':
            result = get_expression(text, pos);
            break;
        default:
            while (pos > 0 && text[pos - 1] != ' ' && text[pos - 1] != '(')
                pos--;
            result = get_word(text, pos);
    }

    printf("%s\n", result);
    free(result);
    return 0;
}

>>55641932
Yep! Well done, anon.

File: C__Data_Users_DefApps_AppData_INTERNETEXPLORER_Temp_Saved Images_1467879701335.jpg (12KB, 286x509px) Image search: [Google]

12KB, 286x509px

>>55639990
>english is not his favorite language

Where are the FPfags? I thought this was their speciality.

var post =
"(QUICK" +
" (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT" +
"  (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))" +
"  (UNDER A (RANDOM CHARACTER POSITION)))" +
" (OR (THIS BIRD) IS GONNA (STAB YOU)))";
var root = post.split(/([\n ()])/)
.reduce((state, t) => ({
  start:  state.start + t.length,
  list: state.list.concat({
    start: state.start,
    len: state.start + t.length,
    token: t,
  }),
}), { start: 0, list: [] })
.list.filter(v => !v.token.match(/^[\n ]*$/))
.reduce((state, v) => {
  if (!state.stack.length)
    state.stack.unshift(state.root);
  switch (v.token) {
    case '(':
      let exp = { start: v.start, val: [] };
      state.stack[0].val.push(exp);
      state.stack.unshift(exp);
      break;
    case ')':
      state.stack[0].len = v.start + 1;
      state.stack.shift();
      break;
    default:
      state.stack[0].val.unshift(v);
      break;
  }
  return state;
}, { root: { start: 0, len: post.length, val: [] }, stack: [] }).root;
function find(n, pos) {
  return n && Array.isArray(n.val)
    && find(n.val.find(v => pos >= v.start && pos < v.len), pos) || n;
}
function print(post, n) {
  console.log(post.substring(n.start, n.len));
}
print(post, find(root, 0));
print(post, find(root, 1));
print(post, find(root, 14));
print(post, find(root, 15));
print(post, find(root, 16));

What the fuck have I done.

birmin no

>>55639777
>>55639990
>>55640167
Where's your reference solution, stupid bird?

>>55644031
[USER WAS STABBED FOR THIS POST]

>>55644082
It's not the real bird though. This faker won't stab me.

File: 1468685002732.jpg (72KB, 720x690px) Image search: [Google]

72KB, 720x690px

>>55644031

#include <time.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define NB '\0'
#define OB '('
#define CB ')'

int main(int argc, char** argv) {
    char* input = "(QUICK\n (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT\n  (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))\n  (UNDER A (RANDOM CHARACTER POSITION)))\n (OR (THIS BIRD) IS GONNA (STAB YOU)))";
    char* current;
    char* deepest = input;
    int level = 0;
    int maxlevel = 0;

    srand(time(NULL));
    for(input + (rand() % strlen(input)); *current != NB; current++) {
        if(*current == OB) {
            level++;
            if(level > maxlevel) {
                maxlevel = level;
                deepest = current + 1;
            }
        } else if(*current == CB) {
            level--;
        }
    }
    for(current = deepest; *current != CB && *current != NB; current++);
    printf("%.*s\n",(int) (current - deepest),deepest);

    return EXIT_SUCCESS;
}

I have no idea how to solve this.. I was thinking the last '(' and the ')' that follow it would be the innermost expression, am I wrong in that regard?

>>55645920
>am I wrong in that regard?
yes, the inner most text is the most nested one
"the last (" doesn't hold up in this example:
(((This is the inner most text))(this is the last bracket))

>>55646418

I literally don't know how I'm going to approach this, and I'm starting CS in college in 2 weeks time.

t-there's still enough time to kill myself right?

>>55646740
>t-there's still enough time to kill myself right?
yes, but you need to start doing so now

import random

a = """    (QUICK      (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT       (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))       (UNDER A (RANDOM CHARACTER POSITION)))      (OR (THIS BIRD) IS GONNA (STAB YOU)))"""

n = random.randint(0, len(a))

for i in range(n, 0, -1):
    char = a[i]
    if char == "(":
        s = a[i+1:].split(")")[0]
        break
    if char == ")":
        for i in range(i, len(a)):
            char = a[i]
            if char == "(":
                s = a[i+1:].split(")")[0]
                break
print n
print s

[\code]

>>55646418

But OP said something different here: >>55640280

>When 1~5, it should return QUICK

This means that Op actually wants the outermost word or expression, or am I wrong?


This is hard to understand..

>>55646777

What's actually the correct way to approach this problem? I'm too scared to kill myself.

>>55639777
I don't get it.
say, if I'm given 7 as an index
then the innermost is the middle from the 7th index to the last index?
so (n + last index) / 2

>>55647171
help you stupid fuckin bird

>>55639777

Is this Lisp?

>>55639777

import Data.List (maximumBy)
import Data.Ord (comparing)

import Text.Parsec
import Text.Parsec.String

expr :: Int -> Parser (Int, String)
expr d = do
    prefix   <- many $ noneOf "()"
    children <- many subExpr
    return . maximumBy (comparing fst) $ (d,prefix) : children
    where subExpr = char '(' *> expr (d+1) <* char ')' <* many (noneOf "()")

λ :l "/mem/inner.hs"
[1 of 1] Compiling Main             ( /mem/inner.hs, interpreted )
Ok, modules loaded: Main.
λ runParser (expr 0) () "OP" "(QUICK (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST)) (UNDER A (RANDOM CHARACTER POSITION))) (OR (THIS BIRD) IS GONNA (STAB YOU)))"
Right (4,"RANDOM CHARACTER POSITION")
λ 

haslel wins again

>>55639777

Here's a Ruby version, I hope I understood this correctly..

#init
input = %q[(QUICK
 (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT
 (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))
 (UNDER A (RANDOM CHARACTER POSITION)))
 (OR (THIS BIRD) IS GONNA (STAB YOU)))] . gsub("\n", '')
output = ""
i_max = input.length
cnt, cnt_max, i = 0, 0, 0

# random start --> find last opening bracket
puts "Starting at position #{i = rand(i_max)}"
while input[i] != "(" and i > 0 do i -= 1 end

# find innermost expression
input[i..-1].each_char do |c|
  if c == "(" then
    cnt += 1
    if cnt > cnt_max then
      cnt_max = cnt
      output = ""
    end 
  elsif c == ")" then
    cnt -= 1
    break if cnt == 0 
  else
     output << c
  end
end

# display result
puts output

>>55647577

I just noticed, that "i_max" is toally senseless here.. meh.

>>55647577

Refactored my code for the lulz:

r, c, c2, i = '', 0,0,0
input = %q[(QUICK (WRITE (A PROGRAM) IN (YOUR FAVORITE
 LANGUAGE) THAT (FINDS THE INNERMOST (WORD OR EXPRESSION)
 OF(THIS POST)) (UNDER A (RANDOM CHARACTER POSITION)))
 (OR (THIS BIRD) IS GONNA (STAB YOU)))] . gsub("\n", '')
 
puts "Starting at position %i" % (i = rand(input.length))
while input[i] != "(" and i > 0 do i -= 1 end
input[i..-1].each_char do |j|
    c += (j == '(' ? 1 : (j == ')' ? -1 : (r << j; 0)))
    c == 0 ? break : (c > c2 ? (c2 = c; r = ''):'')
end
p r

>>55647171
>>55647219
When 7, it's the whole post.

For the string ((a) b):
0 is ((a) b),
1 is (a)"
2 is a
3 is (a)
4 is ((a) b)
5 is b
6 is ((a) b)

>>55648772

Is the innermost expression supposed to be WORD OR EXPRESSION if the position is 0?

>>55648902
Under the position 0 there is only an expression.

>>55648935

As in should my program output "(WORD OR EXPRESSION)" as the innermost loop?

>>55648955
It should output that if the position lands in one of its parenthesis or a space.

>>55649000

So if, assuming the function works correctly, if the random number generated is 0, the innermost expression would be "(WORD OR EXPRESSION)"?

>>55649049
No. "(WORD OR EXPRESSION)" is not located under the position 0.

this problem makes no sense
I guess I getting stabbied.

Post a problem that makes sens better time, kiwibird

Ok almighty bird, I think I got it.
What you call "innermost" is the smallest word or expression the pointer is on.
If on a word, then it returns the word and if on a space or a parenthesis it returns the parenthesis and all that is it in.
tl;dr return smallest grammar token the cursor is on.
Have I successfully understood your question, Stabby Birdy?

>>55649261
Yes.

Although "the parenthesis and all that is it in" is not a single grammar token, you got it.

>>55644031
>stupid bird
kek

>>55649261

Woah that was totally not what I understood, I thought OP just wanted the words inside the innermost loop of the entire string.

>>55649261
I doubt that's it. That's way too easy.

>>55644601
Holy shit, it was a cat the whole time.

>>55651022
Could it be?

fuck this thread

#include <iostream>
#include <cstdlib>
#include <string>
using namespace std;

int main(int argc, char *argv[])
{
    string input = "(QUICK(WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT(FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))(UNDER A (RANDOM CHARACTER POSITION)))(OR (THIS BIRD) IS GONNA (STAB YOU)))";
    int position = atoi(argv[1]);
    int new_pos = 0;
    
    string::iterator it;
    for(it = input.begin() + position; it != input.begin(); --it) {
        if(*it == '(' || *it == ')')
            break;
        ++new_pos;
    }
    for(it = input.begin() + (position - new_pos) + 1; it != input.end(); ++it) {
        if(*it == ')' || *it == '(')
            break;
        cout << *it;
    }
    cout << endl;
    
    return 0;
}

>>55651595
>C++ doesn't have a trim function

>>55651595
>

using namespace std;

>>55639777

    (QUICK
     (WRITE (A PROGRAM) IN (YOUR FAVORITE LANGUAGE) THAT
      (FINDS THE INNERMOST (WORD OR EXPRESSION) OF (THIS POST))
      (UNDER A (RANDOM CHARACTER POSITION)))
     (OR (THIS BIRD) IS GONNA (STAB YOU)))

$res: STAB YOU