Help me understand a calorie /fit/! Calorie is an amount of energy,needed

No, that means it's 250 calories

>>40391015
The chemical energy is food is converted, among other things, as thermal energy in the body.

>>40391015
Stop reaching for excuses fatso.

>americans

File: 1473548191707.jpg (7KB, 245x250px) Image search: [Google]

7KB, 245x250px

Wait wait guys aint gettin it. 100 ml of cola is 42 kcal,thou 250 42*2,5 is ~100? Anyway,so what a calorie is?Does this equasion of coldness and calorie add up,or its complete obsolette bullshit?

>>40391015
>So how low temperature of cola would i need to balance it out?
>T. man who drinks 3 l of cola every single day.
i wouldn't

do you actually think drinking cold coke is cancelling out the calories?

>>40391139
well there have to be point where it does count on minus.It may be on -200 celsius,tho.Would still eat it.

>>40391015
1 cal = enough energy to heat 1mL of water by 1 degree celsius
1 kcal = enough energy to heat 1L of water by 1 degree celsius

coke = 43 kcal / 100ml
3L of coke = 1290 kcal, i.e. enough energy to heat 1L of water by 1290 degrees celsius, or 100L of water by 12.9 degrees celsius

100kg human is roughly equal to 100L of water thermodynamically

so to cancel out the calories, the coke would need to lower your body temperature by 12.9 degrees when you drink it

assuming that human and coke are both fluids and that drinking is analogous to mixing, we can use the formula

T = (m_c * c_c * t_c + m_h * c_h * t_h) / (m_c * c_c + m_h * c_h)
24.1 = (3*t_c + 3700) / (100)

where T is the final temperature (normal body heat lowered by cold coke, 37 - 12.9 = 24.1 degrees)
m_c is the mass of coke (3kg, assuming coke has the same density as water - in reality it would be a little higher)
c_c is the specific heat capacity of coke (again assume the same as water at 1 kcal/kg)
t_c is the initial temperature of coke (unknown)
m_h is the mass of human (100kg)
c_h is the specific heat capacity of human (1 kcal/kg)
t_h is the initial temperature of human (37 degrees)

Substituting in all of our knowns, we solve for t_c = -405.9 degrees Celsius. Absolute zero is around -273 degrees Celsius.

So anon, if you somehow manage to drink coke that's colder absolute zero and not die, and your body uses the sugars to warm itself up, you might just be calorie neutral.

>>40391406
>24.1 = (3*t_c + 3700) / (100)
whoops, ignore that, left my workings in. Should be [24.1 = (3*t_c + 3700) / 103] anyway

>>40391015
OP, chemical energy is not the same as temperature

Think of it this way, if you burn some gasoline, it will give off energy (fire) even if it was cold to start with.
Of course, your body will have to use up some energy to heat up the cola if you drink it cold, but it's a very negligible amount.

You could drink ice water all day, and you'll probably burn more calories from walking to get the water than heating it up.

>>40391439
>>40391421
>>40391406


Okay thank you mates.
Case closed.