First person to solve this for me will receive 0.004 BTC. I

>>2291016
cocks

>>2291029
damnit beat me

>>2291016
Depends, we talking a Lambo or some other worthless car?
3PDCp6uoaHfxxs4FrypzqZkhWjQXVzPrKnm

>>2291029
Wrong
>>2291035
Lambo is longer than 300 cm

>>2291016
We need more data... What is the weight distribution of the car?

>>2291016
Working on it now OP have made an equation

>>2291109
He said it was equally distributed

>>2291109
Why are you trolling so poorly? Read the OP again if serious

>>2291016
16LorZ4dgDk4YrHpGxPavbYgmepYnxmDCJ

1080nm

t = r*F*sin(x)
x = 45deg
sin(45deg) = sqrt(2)/2
r = 280cm
F = 1000kg*g = 9807N
t = 19417 Nm

1DpjL9gvXpgBTk3Cop8oS1ujshzRMm5QCr

>>2291255
>>2291268

There is a weight of 1000kg 40cm behind the rear wheel that is laterally equally distributed... No such data has been given about the weight of the car.... More specifically the front end weight

>>2291796
You need to learn how to read, my friend.
>>2291316
>>2291296
Both of these are almost definitely definitely wrong.

((875)kg*(0.160^2)m)/(2700^2)s = 3.07Nm

1X4nhYVShCdV7YhiodboB1AWMjyaKoRFz

>>2291016
The rear moment counteracts the moments from the first 40 centimeters. We only need to consider the weight from 80cm to 320cms from the wheel. These moments average out to a moment at 200cm of 750 kg. This is a moment of 150Nm.
19wkoLCbVMLBmBTm9CGyKWSmKNgDwzk2uM

>>2292271
The 45 degrees is irrelevant to the question because the car initially must life from 0 degrees. My initial answer was wrong, forgot gravity. 1470 N-m

19wkoLCbVMLBmBTm9CGyKWSmKNgDwzk2uM

>>2292295
If the car needs to sustain 45 degrees it only needs to produce sin(45)*1470.

This is impossible, you don't know the weight of the driver, fuel load, you don't know how much grip the tyres are capable of producing,

>>2291851
>almost definitely

whoops you seem to have typed some retardation, did you want help fixing that?

>>2291016
Do your own homework

File: IMG_20170605_095432.jpg (2MB, 4096x2160px) Image search: [Google]

2MB, 4096x2160px

12,26 kNm to lift off
8671 Nm to remain up

>>2291016
17RbvkbEo7ZxTEHqRPxEANnf6K1QBRgzbZ

I presume the exercise only demands the torque needed for the car to stay upright at 45 degrees.

The answer is 16970.55Nm

The exis of rotation, judging from the instructions, is the rear axle.

Thus, we have a = 280 cm and m1 = 875 kg in from of the axle and b = 40 cm with m2 = 125 kg behind it.

So, when the car is upright at fi = 45 degrees, there are two torques: the one in front and the one behind.

In front: M1 = m1 * g * a * sin(fi) = 17 324.1 Nm
Behind: M2 = m2 * g * b * sin(fi) = 353.55 Nm

Now these torques have the opposite direction. The net torque is then M1 - M2 = 16970.55 Nm, pulling the front down. You need the same amount at the rear axle to keep it at the angle.

what kind of tires is OP using? if normal profile tires no amount of torque is going to do shit for you, you will just do a burnout every single time and not a wheelie

All answers here are wrong, you are all doimg calculations by asumim that car is 2 particles that are some distance from axis. To do this calculation you need to calculate moment of inertia for thin rod (that must be assumed since op didnt say anithing about height or with) and then you ballance the torques.

>>2292539
he's right I forgot they're opposing so:
takeoff: 11,8 kNm
stay at 45°: 8324 Nm
(you forgot that you have to divide the distance by 2 because the weight is in the middle)
I'm still the first with the correct solution

File: 1477083215774.jpg (60KB, 700x406px) Image search: [Google]

60KB, 700x406px

also mfw OP is posting this from his FWD Nissan Cuckwagon dreaming about an actual car

>>2292619
its a physics question, not a real world one..
>>2292630
OP wants to know what torque a car needs to do this. so there are 2 solutions here: the amount it needs to get moving, and the amount it needs to stay up. get your dynamics out of here.

>>2292640
Weight is uniformly distributed, its not in the middle.

>>2292670
have you ever attended a physics class?

>>2292669
>its a physics question, not a real world one..
this is a stupid fucking thread and on a wrong board

>>2292679
What i am saying it that to get the rigt answer you must use formula T=Ia where I is moment of inertia of a thin rod, noone here seams to underatand basic solid body physics. You cant just say T=La for solid object, this only works for particles. Fuck i the reward was bigger i would have solved this problem but watchig you all strugle is the reward in itself

>>2292701
Why dont you set the problem infitesimaly and do the integral, then come back and se if those answers are right.

>>2292640
Damn it. Where is your BTC address though?

>>2292731
"how much needs to be produced" was the question. it's not about dynamics.the point is to calculate the current torque due to gravity, which gives 11,8 kNm. any torque higher than that will lift the nose up. it WILL move. you just have get the throttle down to stop at the right point. great that you know about inertia, but it is not required here.
>>2292760
not expecting OP to deliver honestly
168SvnFtw9z6NiNf7w69QFm6rnK1VePy4j

>>2292760
Right here OP

0xe4e6bF2EF8ddE56e077C115d219f75F4FA0cE1db

>>2292847
isn't that an ETH address? also, there are IDs here you know

>>2292312
This guy gets it...

Anyone attempting to answer this question with unsubstantial data being provided should just GTFO

The only equation that needs to be solved is how to get my dick near some pussy

1LC8NGvxh1fDEh1kRU21it2874xvXoHTUi