After 9 years of graduating from highschool, I finally got the

i will, give me a second

Tip: When you move a term from the top to bottom (or bottom to top) you change the sign of the exponent.

For example, b^-2 on top becomes b^2 on the bottom.

add powers of b and d including the signs

ie power of b in the numerator will be -2+1=-1
d will be 3+1

>>722389149
ans is 1/32 d^25/b^20

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1

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2

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3

and done, it's easy algebra

Look at the numbers. You've got 2 x 3 on top and 12 on the bottom. So that's 6/12 which is just 1/2.

Then look at the b. You've got b^-2 * b on top and b^3 on the bottom. Well, b^3 on bottom is the same as b^-3 on top. So add together the exponents and that's b^(-2+1-3) which is b^-4. If you're wondering where I got the +1 from it's because b is the same as b^1, and the -3 comes from the b^3 on the bottom becoming b^-3 on top.

Then look at the d. The d^-1 on the bottom is the same as d^1 on top. So you've got d * d^3 * d^1 (keep in mind that d and d^1 is the same thing) which is d^(1+3+1) = d^5.

So you've got 1/2 * b^-3 * d^5.

From the 1/2 you've got the 1 on top and the 2 on the bottom. From the b^-3 you've got b^3 on the bottom. And from the d^5 you've got d^5 on the top.

So that's (d^5) / (2 * b^3).

Finally, the whole thing is raised ^5 so you just multiply all the exponents by 5.

You get d^25 / (2^5 b^15)

= d^25 / 32b^15

Hope that helps. Follow each step to understand what I'm doing (and hopefully I didn't make any mistake).

>>722389369
Oops, I made a mistake. Where I wrote "So you've got 1/2 * b^-3 * d^5" it should be "So you've got 1/2 * b^-4 * d^5" and it ends up as d^25 / 32b^20.

>>722389369
Good explanation. But one mistake:

> So add together the exponents and that's b^(-2+1-3) which is b^-4.

> So you've got 1/2 * b^-3 * d^5.

You lost a b there, so the final answer should be d^25 / (32*b^20)

>>722389369
>>722389570
Thank you very much for taking the time. Even though English is not my native language I could understand the process perfectly.

I got one last question if possible, regarding another kind of excercise

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I already made a few excercises of this kind, but this one in particularhas me spinning. Might be easy but can't figure it out.

>>722390169
faggot, i helped you too >:(
>>722389240
>>722389266
>>722389287

>>722390726
My apologies, thanks for your help too, meant no harm. Only saw the last one. Took me a bit longer to understand it from ur side but also worked!

>>722390848
lol, sorry for calling you faggot, I'm trying to solve this too:
>>722390368

>>722388138
curious but, you're going into a university and don't know algebra that is taught in middle school?

>>722390368
take cube root of both sides
also 3.3^n+1 = 3^n+2

therefore it says (3^n+2 + 3^n+2):(3^n+2)=2
Dividing by 3^n+2 we get 2:1=2 which is always true thus this is true for any value of n

>>722391075
I do know, the thing is that after such a long time of not using any of the concepts, things kinda got forgotten.

>>722391255
Oh I see
I'm the same anon as >>722391220
btw

d^25/32b^20

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>>722390368
Tutor-fag here, but I'm getting offline shortly.

Here, I typed this up in MathType.

The ":" means a ratio, or division.

>>722391334
>>722391486
Thank you both. I feel really dumb now after seeing how it's done. Although I had a vague idea, couldn't help myself.

Thanks to everyone that helped a faggot get his math crap right.