Can anyone help me set this up and solve? Consider the 52.0-kg

sum of all forces must equal zero on the woman
T + W + Fwall = 0
split into x and y components and solve

Also keep in mind that friction scales with force applied perpendicular to the surface, so you'll have to use the Flegs, some trig and this 15 degree angle to calculate that.

>>18415796
But what about N force extending opposite of Flegs?

>>18415815
Is there anyway you could show me?

Would weight be straight down, opposite of T, or would it

>>18415815
>>18415796
When I do this I get

X -comp
Fcos15 = Tsin31

Y-comp
Fsin15+Tcos31=509.6N

I don't know where to continue

>>18415839
bump

File: CalculusWasAMistake.jpg (106KB, 720x561px) Image search: [Google]

106KB, 720x561px

>>18415783
The tension and the force from her legs are both at angles, so you separate these into components. You know that the force excreted by her legs in the y direction must be equal to the force of tension in the y direction and her weight ,since the system is in equilibrium.

For the friction part you know that her legs must provide a certain amount of force for the system to be in equilibrium. This force is provided by friction, thus you can derive the coefficient of friction from this.

>>18415839
solve the 2 simultaneous equations. You have 2 unknowns and 2 eqns, so you will get a unique answer for F and T.