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How the are you supposed to simplify sin(2t)-tan(t)...
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You are currently reading a thread in /wsr/ - Worksafe Requests

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How the are you supposed to simplify sin(2t)-tan(t) any further?

Every website I've looked at recognizes that form as the simplest.
>>
Maybe they consider sin(2t) to be more complex than 2sin(t)cos(t)
>>
Sin (2t) - tan (t)
2sin (t)cos (t) - sin (t)/cos (t)
[Sin (t)/cos (t)]•[2cos^2 (t) - 1]
Tan (t)•[cos (2t)]

Yeah I need more context to know what they consider to be more simplified.
>>
>>53841
You helped a lot. Just trying to make sure I completely understand the transitions.
>>
>>53841
How did you go from:

2sin (t)cos (t) - sin (t)/cos (t)
[Sin (t)/cos (t)]•[2cos^2 (t) - 1]

on the right side. I understand relating the first part to 2cost^2-1, but how do you go from subtracting sin (t)/cost(t) to multiplying it?
>>
Fuck off, nerds :)
>>
>>53841
I don't understand where the negative symbol for sin (t)/cos (t) goes? I've seen the end result one other random place as an option, but I've yet to see how you turn:

2cos^2 (t) -1 - tan (t)

into

tan (t) 2cos^2 (t) - 1
>>
>>53856
Factor out sin/cos. I sorta skipped a step.

2sin (t)cos (t) - sin (t)/cos (t)
2sin (t)cos^2 (t)/cos (t) - sin (t)/cos (t)
[Sin (t)/cos (t)]•[2cos^2 (t) - 1]

Does that help?
Thread replies: 8
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