I'm lost, can someone tell me how to do this?

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I'm lost, can someone tell me how to do this?

I got to

cosx/(sinx/cosx) = cosx*(cosx/sinx) = cos^2x/sinx = 1-sin^2x/sinx ???

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>>39820

Dude, that's bait. It's not an equality.

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=> cos*sin = (1-cos)(sin/cos)

=> cos = (1-cos)/cos

=> cos^2 =(1-cos)

so it is only true for all x if (1-cos) had been (1-sin^2)

unless you want to solve it for a specific x value

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>>39837

which has solution x = 0.904

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>>39833

>>39826

The question asked for which of the 4 isn't an identity, and the textbook answer is b.

So either this is an identity or the textbook went full retard like 1/3 of the time.

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>>39850

>facepalm.jpg

The left side should be [ (1 - cos x) / cos x ] / tan x . That top line belongs to d, not c.

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>>39861

well shit

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>>39861

then it's actually easy to see:

multiply by (sin x tan x)/(1-cos x) and you obtain:

sin x / cos x = tan x

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>>39937

i think the issue here was he read the problem wrong. its pretty obvious how b. isnt an identity and the rest are.

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