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x y z 1 -1 0 d -1 0 2 d .5 .5 -1 d It reduced to: x y z 1 0

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Thread replies: 8
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x y z
1 -1 0 d
-1 0 2 d
.5 .5 -1 d

It reduced to:
x y z
1 0 0 4d
0 1 0 3d
0 0 1 5d/2
_____________________

I end up with
x y z
1 0 0 d^2
0 1 0 3d
0 0 1 -d+d^2

What am I doing wrong? Can someone explain the steps?
>>
>>7798372
>What am I doing wrong
you're posting baby's first freshmen linear algebra homework on /sci/
>>
>>7798383
Technically this board is science AND math lol
>>
>tfw /sci/ can't even answer a simple math question
kek
>>
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>linear algebra
so fucking casual
>>
>>7798446
the majorty of sci is highschoolers and retard undergraduate freshmans

the ones that actually know anything refuse to answer anything below analysis
>>
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>>7798372
Honestly, I have no idea why you squared row 1.
The legal operations are multiplying a row by a constant and adding rows.

The basic gameplan is to first get all values in each row to be an integer.
Next, add and subtract rows from one another to get zeroes, until one row only has one value in it.
Divide that row by that value so that it is a row with 0s and a 1.
Add and subtract that row as needed to get all rows to have 0s in that row.
Rinse and repeat
Then you can rearrange your columns to be nice and neat and in order, but it's not really necessary unless you really want it to be the identity matrix, or having a matrix that looks like:
>x y z
>1 0 0 4d
>0 0 1 5d/2
>0 1 0 3d

In the future, instead of posting your solution and asking for others to say where your work went wrong, you might want to post your actual work.
That, or don't ask /sci/ to do your math homework at all.
>>
>>7798878
>or you are triggered by a matrix that looks like:
oops
Thread posts: 8
Thread images: 3


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